Python – Sort String by Custom Integer Substrings
Given a list of strings, sort strings by the occurrence of substring from list.
Input : test_list = [“Good at 4”, “Wake at 7”, “Work till 6”, “Sleep at 11”], subord_list = [“11”, “7”, “4”, “6”]
Output : [‘Sleep at 11’, ‘Wake at 7’, ‘Good at 4’, ‘Work till 6’]
Explanation : Strings sorted by substring presence.Attention geek! Strengthen your foundations with the Python Programming Foundation Course and learn the basics.
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Input : test_list = [“Good at 9”, “Wake at 7”, “Work till 6”, “Sleep at 11”], subord_list = [“11”, “7”, “9”, “6”]
Output : [‘Sleep at 11’, ‘Wake at 7’, ‘Good at 9’, ‘Work till 6’]
Explanation : Strings sorted by substring presence.
Method #1 : Using sorted() + zip() + lambda + regex()
The combination of above functions can be used to solve this problem. In this, we perform task of sorting by substring using regex() and sorted(), zip() is used to produce end result.
Python3
# Python3 code to demonstrate working of# Sort String by Custom Substrings# Using sorted() + zip() + lambda + regex()import re# initializing listtest_list = ["Good at 4", "Wake at 7", "Work till 6", "Sleep at 11"]# printing original listprint("The original list : " + str(test_list))# initializing substring listsubord_list = ["6", "7", "4", "11"]# creating inverse mapping with indextemp_dict = {val: key for key, val in enumerate(subord_list)}# custom sortingtemp_list = sorted([[ele, temp_dict[re.search("(\d+)$", ele).group()]] \ for ele in test_list], key = lambda x: x[1])# compiling resultres = [ele for ele in list(zip(*temp_list))[0]] # printing resultprint("The sorted list : " + str(res)) |
The original list : ['Good at 4', 'Wake at 7', 'Work till 6', 'Sleep at 11'] The sorted list : ['Work till 6', 'Wake at 7', 'Good at 4', 'Sleep at 11']
Method #2 : Using sorted() + zip() + comparator + regex()
This is yet another way in which this task can be performed. In this similar functionality is used as above method, difference is that comparator function is fed to sorted() rather than lambda to sort.
Python3
# Python3 code to demonstrate working of# Sort String by Custom Substrings# Using sorted() + comparator + regex()import re# helper function to solve problemdef hlper_fnc(ele): temp = re.search("(\d+)$", ele).group() return temp_dict[temp] if temp in temp_dict else int(temp)# initializing listtest_list = ["Good at 4", "Wake at 7", "Work till 6", "Sleep at 11"]# printing original listprint("The original list : " + str(test_list))# initializing substring listsubord_list = ["6", "7", "4", "11"]# creating inverse mapping with indextemp_dict = {val: key for key, val in enumerate(test_list)}# sorting using comparatortest_list.sort(key = lambda ele: hlper_fnc(ele)) # printing resultprint("The sorted list : " + str(test_list)) |
The original list : ['Good at 4', 'Wake at 7', 'Work till 6', 'Sleep at 11'] The sorted list : ['Good at 4', 'Work till 6', 'Wake at 7', 'Sleep at 11']
