Python | Sort list of tuples by specific ordering
The normal sorting of tuples has been dealt previously. This article aims at sorting the given list of tuples by the second element, based on the order provided in some list.
Method #1 : Using list comprehension + filter() + lambda
Above three functions can be combined to perform the particular task in which list comprehension performs the iteration, lambda function is used as helper function for filtering to sort according to second element of tuple.
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# Python3 code to demonstrate# sort list of tuples according to second# using list comprehension + filter() + lambda # initializing list of tuplestest_list = [('a', 2), ('c', 3), ('d', 4)] # initializing sort order sort_order = [4, 2, 3] # printing the original listprint ("The original list is : " + str(test_list)) # printing sort order list print ("The sort order list is : " + str(sort_order)) # using list comprehension + filter() + lambda# sort list of tuples according to secondres = [i for j in sort_order for i in filter(lambda k: k[1] == j, test_list)] # printing resultprint ("The list after appropriate sorting : " + str(res)) |
The original list is : [('a', 2), ('c', 3), ('d', 4)]
The sort order list is : [4, 2, 3]
The list after appropriate sorting : [('d', 4), ('a', 2), ('c', 3)]
Method #2 : Using sorted() + index() + lambda
The sorted function can be used to sort according to order specified. The index function specifies that second element of tuple has to be taken into considerations and all are joined with help of lambda.
# Python3 code to demonstrate# sort list of tuples according to second# using sorted() + index() + lambda # initializing list of tuplestest_list = [('a', 2), ('c', 3), ('d', 4)] # initializing sort order sort_order = [4, 2, 3] # printing the original listprint ("The original list is : " + str(test_list)) # printing sort order list print ("The sort order list is : " + str(sort_order)) # using sorted() + index() + lambda# sort list of tuples according to secondres = list(sorted(test_list, key = lambda i: sort_order.index(i[1]))) # printing resultprint ("The list after appropriate sorting : " + str(res)) |
The original list is : [('a', 2), ('c', 3), ('d', 4)]
The sort order list is : [4, 2, 3]
The list after appropriate sorting : [('d', 4), ('a', 2), ('c', 3)]
