Given a list of non-negative numbers, the task is to sort these integers according to the sum of their digits.

**Examples:**

Input :[12, 10, 106, 31, 15]Output :[10, 12, 31, 15, 106]Input :[1111, 19, 29, 11, 12, 9]Output :[11, 12, 1111, 9, 19, 29]

Let’s discuss few Pythonic ways to do this task.

**Approach #1 : ** List comprehension

Using for loop to convert each element of list to a different list with its digits as elements. Now, use the sorted function with the above-mentioned function as *key*.

`# Python3 Program to Sort list of ` `# integers according to sum of digits ` ` ` `def` `sortList(lst): ` ` ` `digits ` `=` `[` `int` `(digit) ` `for` `digit ` `in` `str` `(lst) ] ` ` ` `return` `sum` `(digits) ` ` ` `# Driver Code ` `lst ` `=` `[` `12` `, ` `10` `, ` `106` `, ` `31` `, ` `15` `] ` `print` `(` `sorted` `(lst, key ` `=` `sortList))` |

*chevron_right*

*filter_none*

**Output:**

[10, 12, 31, 15, 106]

**Approach #2 : ** Using `map()`

This approach is similar to the above approach with a slight difference that instead of for loop, we use `map()`

to convert each element of list to a different list with its digit as elements and then follow the similar approach as above.

`# Python3 Program to Sort list of ` `# integers according to sum of digits ` ` ` `def` `sortList(num): ` ` ` `return` `sum` `(` `map` `(` `int` `, ` `str` `(num))) ` ` ` `# Driver Code ` `lst ` `=` `[` `12` `, ` `10` `, ` `106` `, ` `31` `, ` `15` `] ` `result ` `=` `sorted` `(lst, key ` `=` `sortList) ` `print` `(result) ` |

*chevron_right*

*filter_none*

**Output:**

[10, 12, 31, 15, 106]

There is also a one-liner alternative to the above mentioned approach.

`def` `sortList(lst): ` ` ` `return` `sorted` `(lst, key ` `=` `lambda` `x:(` `sum` `(` `map` `(` `int` `, ` `str` `(x))))) ` |

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