# Python | Sort given list by frequency and remove duplicates

• Last Updated : 11 May, 2020

Problems associated with sorting and removal of duplicates is quite common in development domain and general coding as well. The sorting by frequency has been discussed, but sometimes, we even wish to remove the duplicates without using more LOC’s and in a shorter way. Let’s discuss certain ways in which this can be done.

Method #1 : Using count() + set() + sorted()

The sorted function can be used to sort the elements as desired, the frequency can be computed using the count function and removal of duplicates can be handled using the set function.

 `# Python3 code to demonstrate``# sorting and removal of duplicates``# Using sorted() + set() + count()`` ` `# initializing list``test_list ``=` `[``5``, ``6``, ``2``, ``5``, ``3``, ``3``, ``6``, ``5``, ``5``, ``6``, ``5``]`` ` `# printing original list``print``(``"The original list : "` `+` `str``(test_list))`` ` `# using sorted() + set() + count()``# sorting and removal of duplicates``res ``=` `sorted``(``set``(test_list), key ``=` `lambda` `ele: test_list.count(ele))`` ` `# print result``print``(``"The list after sorting and removal : "` `+` `str``(res))`

Output :

```The original list : [5, 6, 2, 5, 3, 3, 6, 5, 5, 6, 5]
The list after sorting and removal : [2, 3, 6, 5]
```

Method #2 : Using `Counter.most_common()` + list comprehension

If one has a particular use case of sorting by the decreasing order of frequency, one can also use most-common function of Counter library to get frequency part.

 `# Python3 code to demonstrate``# sorting and removal of duplicates``# Using Counter.most_common() + list comprehension``from` `collections ``import` `Counter`` ` `# initializing list``test_list ``=` `[``5``, ``6``, ``2``, ``5``, ``3``, ``3``, ``6``, ``5``, ``5``, ``6``, ``5``]`` ` `# printing original list``print``(``"The original list : "` `+` `str``(test_list))`` ` `# using Counter.most_common() + list comprehension``# sorting and removal of duplicates``res ``=` `[key ``for` `key, value ``in` `Counter(test_list).most_common()]`` ` `# print result``print``(``"The list after sorting and removal : "` `+` `str``(res))`

Output :

```The original list : [5, 6, 2, 5, 3, 3, 6, 5, 5, 6, 5]
The list after sorting and removal : [5, 6, 3, 2]
```

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