Python | Sort each String in String list
Sometimes, while working with Python, we can have a problem in which we need to perform the sort operation in all the Strings that are present in a list. This problem can occur in general programming and web development. Let’s discuss certain ways in which this problem can be solved.
Method #1 : Using list comprehension + sorted() + join()
This is one way in which this problem can be solved. In this, we use sorted() functionality to perform sort operation and join() is used to reconstruct the string list.
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# Python3 code to demonstrate working of# Sort Strings in String list# using list comprehension + sorted() + join() # initialize list test_list = ['gfg', 'is', 'good'] # printing original list print("The original list : " + str(test_list)) # Sort Strings in String list# using list comprehension + sorted() + join()res = [''.join(sorted(ele)) for ele in test_list] # printing resultprint("List after string sorting : " + str(res)) |
The original list : ['gfg', 'is', 'good'] List after string sorting : ['fgg', 'is', 'dgoo']
Method #2 : Using map() + sorted() + join() + lambda
The combination of above method can also be used to perform this task. In this, we perform the functionality of traversal using map() and lambda rather than list comprehension.
# Python3 code to demonstrate working of# Sort Strings in String list# using map() + sorted() + join() + lambda # initialize list test_list = ['gfg', 'is', 'good'] # printing original list print("The original list : " + str(test_list)) # Sort Strings in String list# using map() + sorted() + join() + lambdares = list(map(lambda ele: "".join(sorted(ele)), test_list)) # printing resultprint("List after string sorting : " + str(res)) |
The original list : ['gfg', 'is', 'good'] List after string sorting : ['fgg', 'is', 'dgoo']
