Python | Sort each String in String list

Sometimes, while working with Python, we can have a problem in which we need to perform the sort operation in all the Strings that are present in a list. This problem can occur in general programming and web development. Let’s discuss certain ways in which this problem can be solved.

Method #1 : Using list comprehension + sorted() + join()
This is one way in which this problem can be solved. In this, we use sorted() functionality to perform sort operation and join() is used to reconstruct the string list.

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# Python3 code to demonstrate working of
# Sort Strings in String list
# using list comprehension + sorted() + join()
  
# initialize list 
test_list = ['gfg', 'is', 'good']
  
# printing original list 
print("The original list : " + str(test_list))
  
# Sort Strings in String list
# using list comprehension + sorted() + join()
res = [''.join(sorted(ele)) for ele in test_list]
  
# printing result
print("List after string sorting : " + str(res))

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Output :          


The original list : ['gfg', 'is', 'good']
List after string sorting : ['fgg', 'is', 'dgoo']





 


Method #2 : Using map() + sorted() + join() + lambda

The combination of above method can also be used to perform this task. In this, we perform the functionality of traversal using map() and lambda rather than list comprehension.











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# Python3 code to demonstrate working of 


# Sort Strings in String list 


# using map() + sorted() + join() + lambda 


  


# initialize list  


test_list = ['gfg', 'is', 'good'] 


  


# printing original list  


print("The original list : " + str(test_list)) 


  


# Sort Strings in String list 


# using map() + sorted() + join() + lambda 


res = list(map(lambda ele: "".join(sorted(ele)), test_list)) 


  


# printing result 


print("List after string sorting : " + str(res)) 



















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Output :          


The original list : ['gfg', 'is', 'good']
List after string sorting : ['fgg', 'is', 'dgoo']








    

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