Python | Sort each String in String list

Sometimes, while working with Python, we can have a problem in which we need to perform the sort operation in all the Strings that are present in a list. This problem can occur in general programming and web development. Let’s discuss certain ways in which this problem can be solved.

Method #1 : Using list comprehension + sorted() + join()
This is one way in which this problem can be solved. In this, we use sorted() functionality to perform sort operation and join() is used to reconstruct the string list.

# Python3 code to demonstrate working of
# Sort Strings in String list
# using list comprehension + sorted() + join()

# initialize list
test_list = ['gfg', 'is', 'good']

# printing original list
print("The original list : " + str(test_list))

# Sort Strings in String list
# using list comprehension + sorted() + join()
res = [''.join(sorted(ele)) for ele in test_list]

# printing result
print("List after string sorting : " + str(res))

Output :

The original list : ['gfg', 'is', 'good']
List after string sorting : ['fgg', 'is', 'dgoo']

Method #2 : Using map() + sorted() + join() + lambda
The combination of above method can also be used to perform this task. In this, we perform the functionality of traversal using map() and lambda rather than list comprehension.

# Python3 code to demonstrate working of
# Sort Strings in String list
# using map() + sorted() + join() + lambda

# initialize list
test_list = ['gfg', 'is', 'good']

# printing original list
print("The original list : " + str(test_list))

# Sort Strings in String list
# using map() + sorted() + join() + lambda
res = list(map(lambda ele: "".join(sorted(ele)), test_list))

# printing result
print("List after string sorting : " + str(res))

Output :

The original list : ['gfg', 'is', 'good']
List after string sorting : ['fgg', 'is', 'dgoo']