Given a dictionary, sort according to descended values, if similar values, then by keys lexicographically.
Input : test_dict = {“gfg” : 1, “is” : 1, “best” : 1, “for” : 1, “geeks” : 1}
Output : {“best” : 1, “is” : 1, “for” : 1, “geeks” : 1, “gfg” : 1}
Explanation : All values are equal, hence lexicographically sorted keys.Input : test_dict = {“gfg” : 5, “is” : 4, “best” : 3, “for” : 2, “geeks” : 1}
Output : {“gfg” : 5, “is” : 4, “best” : 3, “for” : 2, “geeks” : 1}
Explanation : All values are different, hence descending ordered sorted.
Method : Using sorted() + items() + dictionary comprehension + lambda
The combination of above functions can be used to solve this problem. In this, we perform task of sorting using sorted(), dictionary comprehension is used to remake dictionary, items() is used to extract items to sorted.
Python3
# Python3 code to demonstrate working of # Sort Dictionary by Values and Keys # Using sorted() + items() + dictionary comprehension + lambda # initializing dictionary test_dict = {"Gfg" : 1, "is" : 3, "Best" : 2, "for" : 3, "Geeks" : 2} # printing original dictionary print("The original dictionary is : " + str(test_dict)) # - sign for descended values, omit if low-high sorting required res = {val[0] : val[1] for val in sorted(test_dict.items(), key = lambda x: (-x[1], x[0]))} # printing result print("Sorted dictionary : " + str(res)) |
The original dictionary is : {'Gfg': 1, 'is': 3, 'Best': 2, 'for': 3, 'Geeks': 2}
Sorted dictionary : {'for': 3, 'is': 3, 'Best': 2, 'Geeks': 2, 'Gfg': 1}
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