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# Python – Sort by Frequency of second element in Tuple List

• Last Updated : 02 Sep, 2020

Given list of tuples, sort by frequency of second element of tuple.

Input : test_list = [(6, 5), (1, 7), (2, 5), (8, 7), (9, 8), (3, 7)]
Output : [(1, 7), (8, 7), (3, 7), (6, 5), (2, 5), (9, 8)]
Explanation : 7 occurs 3 times as 2nd element, hence all tuples with 7, are aligned first.

Input : test_list = [(1, 7), (8, 7), (9, 8), (3, 7)]
Output : [(1, 7), (8, 7), (3, 7), (9, 8)]
Explanation : 7 occurs 3 times as 2nd element, hence all tuples with 7, are aligned first.

Method #1 : Using sorted() + loop + defaultdict() + lambda

In this, we compute the frequency using defaultdict() and use this result to pass as param to lambda function to perform sorting using sorted() on basis of it.

## Python3

 `# Python3 code to demonstrate working of ``# Sort by Frequency of second element in Tuple List``# Using sorted() + loop + defaultdict() + lambda``from` `collections ``import` `defaultdict`` ` `# initializing list``test_list ``=` `[(``6``, ``5``), (``2``, ``7``), (``2``, ``5``), (``8``, ``7``), (``9``, ``8``), (``3``, ``7``)]`` ` `# printing original list``print``(``"The original list is : "` `+` `str``(test_list))`` ` `# constructing mapping``freq_map ``=` `defaultdict(``int``)``for` `idx, val ``in` `test_list:``    ``freq_map[val] ``+``=` `1`` ` `# performing sort of result ``res ``=` `sorted``(test_list, key ``=` `lambda` `ele: freq_map[ele[``1``]], reverse ``=` `True``)`` ` `# printing results``print``(``"Sorted List of tuples : "` `+` `str``(res))`
Output
```The original list is : [(6, 5), (2, 7), (2, 5), (8, 7), (9, 8), (3, 7)]
Sorted List of tuples : [(2, 7), (8, 7), (3, 7), (6, 5), (2, 5), (9, 8)]
```

Method #2 : Using Counter() + lambda + sorted()

In this, the task of frequency computation is done using Counter(), rest all functionality is similar to above method.

## Python3

 `# Python3 code to demonstrate working of ``# Sort by Frequency of second element in Tuple List``# Using Counter() + lambda + sorted()``from` `collections ``import` `Counter`` ` `# initializing list``test_list ``=` `[(``6``, ``5``), (``2``, ``7``), (``2``, ``5``), (``8``, ``7``), (``9``, ``8``), (``3``, ``7``)]`` ` `# printing original list``print``(``"The original list is : "` `+` `str``(test_list))`` ` `# constructing mapping using Counter``freq_map ``=` `Counter(val ``for` `key, val ``in` `test_list)`` ` `# performing sort of result ``res ``=` `sorted``(test_list, key ``=` `lambda` `ele: freq_map[ele[``1``]], reverse ``=` `True``)`` ` `# printing results``print``(``"Sorted List of tuples : "` `+` `str``(res))`
Output
```The original list is : [(6, 5), (2, 7), (2, 5), (8, 7), (9, 8), (3, 7)]
Sorted List of tuples : [(2, 7), (8, 7), (3, 7), (6, 5), (2, 5), (9, 8)]
```

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