Python – Skew Nested Tuple Summation

Given a Tuple, nesting at 2nd position, return summation of 1st elements.

Input : test_tup = (5, (6, (1, (9, None))))
Output : 21
Explanation : 9 + 6 + 5 + 1 = 21.

Input : test_tup = (5, (6, (1, None)))
Output : 12
Explanation : 1 + 6 + 5 = 12.

Method #1 : Using infinite loop

In this, we perform get into skew structure while summation using infinite loop and break when we reach None value.



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# Python3 code to demonstrate working of 
# Skew Nested Tuple Summation
# Using infinite loop
  
# initializing tuple
test_tup = (5, (6, (1, (9, (10, None)))))
  
# printing original tuple
print("The original tuple is : " + str(test_tup))
  
res = 0
while test_tup:
    res += test_tup[0]
      
    # assigning inner tuple as original
    test_tup = test_tup[1]
  
# printing result 
print("Summation of 1st positions : " + str(res)) 

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Output

The original tuple is : (5, (6, (1, (9, (10, None)))))
Summation of 1st positions : 31

Method #2 : Using recursion

In this, we perform summation and recur for the 2nd element of tuple,  return on None.

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# Python3 code to demonstrate working of 
# Skew Nested Tuple Summation
# Using recursion
  
# helper function to perform task
def tup_sum(test_tup):
      
    # return on None 
    if not test_tup:
        return 0
    else:
        return test_tup[0] + tup_sum(test_tup[1])
  
# initializing tuple
test_tup = (5, (6, (1, (9, (10, None)))))
  
# printing original tuple
print("The original tuple is : " + str(test_tup))
  
# calling fnc.
res = tup_sum(test_tup)
  
# printing result 
print("Summation of 1st positions : " + str(res)) 

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Output

The original tuple is : (5, (6, (1, (9, (10, None)))))
Summation of 1st positions : 31

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