Python – Similar index pairs in Tuple lists

Sometimes, while working with Python tuples, we can have a problem in which we need to perform similar index pairing. This kind of problem is peculiar, but can occur across certain domains. Let’s discuss certain way in which this task can be performed.

Input :
test_list1 = [(5, ), (1, ), (8, ), (10, )]
test_list2 = [(8, ), (1, ), (11, ), (9, )]
Output : [[(5, 8)], [(1, 1)], [(8, 11)], [(10, 9)]]

Input :
test_list1 = [(5, 6, 7, 6)]
test_list2 = [(8, 6, 7, 9)]
Output : [[(5, 8), (6, 6), (7, 7), (6, 9)]]

Method : Using list comprehension + zip()
The combination of above functions can be used to solve this problem. In this, we perform the task of zipping similar index elements using zip() and list comprehension is used to compile all the pairs.

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# Python3 code to demonstrate working of 
# Similar index pairs in Tuple lists
# Using list comprehension + zip()
  
# initializing lists
test_list1 = [(5, 6), (1, 2), (8, 9), (10, 33)]
test_list2 = [(8, 7), (1, 3), (11, 23), (9, 4)]
  
# printing original list
print("The original list 1 is : " + str(test_list1))
print("The original list 2 is : " + str(test_list2))
  
# Similar index pairs in Tuple lists
# Using list comprehension + zip()
res = [list(zip(a, b)) for a, b in zip(test_list1, test_list2)]
  
# printing result 
print("The paired tuples : " + str(res)) 

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Output :          


The original list 1 is : [(5, 6), (1, 2), (8, 9), (10, 33)]
The original list 2 is : [(8, 7), (1, 3), (11, 23), (9, 4)]
The paired tuples : [[(5, 8), (6, 7)], [(1, 1), (2, 3)], [(8, 11), (9, 23)], [(10, 9), (33, 4)]]






    

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