Python – Similar characters Strings comparison

Given two Strings, separated by delim, check if both contain same characters.

Input : test_str1 = ‘e!e!k!s!g’, test_str2 = ‘g!e!e!k!s’, delim = ‘!’
Output : True
Explanation : Same characters, just diff. positions.

Input : test_str1 = ‘e!e!k!s’, test_str2 = ‘g!e!e!k!s’, delim = ‘!’
Output : False
Explanation : g missing in 1st String.

Method #1 : Using sorted() + split()

In this, we perform split using split(), and then perform task of sorting to get strings in order, post that strings are compared using the comparison operator.

Python3

# Python3 code to demonstrate working of
# Similar characters Strings comparison
# Using split() + sorted()

# initializing strings
test_str1 = 'e:e:k:s:g'
test_str2 = 'g:e:e:k:s'

# printing original strings
print("The original string 1 is : " + str(test_str1))
print("The original string 2 is : " + str(test_str2))

# initializing delim
delim = ':'

# == operator is used for comparison
res = sorted(test_str1.split(':')) == sorted(test_str2.split(':'))

# printing result
print("Are strings similar : " + str(res))

Output

The original string 1 is : e:e:k:s:g
The original string 2 is : g:e:e:k:s
Are strings similar : True

Method #2 : Using set() + split()

In this, instead of sort(), we convert strings to set(), to get ordering. This works only on unique character strings.

Python3

# Python3 code to demonstrate working of
# Similar characters Strings comparison
# Using set() + split()

# initializing strings
test_str1 = 'e:k:s:g'
test_str2 = 'g:e:k:s'

# printing original strings
print("The original string 1 is : " + str(test_str1))
print("The original string 2 is : " + str(test_str2))

# initializing delim
delim = ':'

# == operator is used for comparison
# removes duplicates and compares
res = set(test_str1.split(':')) == set(test_str2.split(':'))

# printing result
print("Are strings similar : " + str(res))

Output

The original string 1 is : e:k:s:g
The original string 2 is : g:e:k:s
Are strings similar : True