Python – Similar characters Strings comparison
Given two Strings, separated by delim, check if both contain same characters.
Input : test_str1 = ‘e!e!k!s!g’, test_str2 = ‘g!e!e!k!s’, delim = ‘!’
Output : True
Explanation : Same characters, just diff. positions.Input : test_str1 = ‘e!e!k!s’, test_str2 = ‘g!e!e!k!s’, delim = ‘!’
Output : False
Explanation : g missing in 1st String.
Method #1 : Using sorted() + split()
In this, we perform split using split(), and then perform task of sorting to get strings in order, post that strings are compared using the comparison operator.
Python3
# Python3 code to demonstrate working of # Similar characters Strings comparison# Using split() + sorted() # initializing stringstest_str1 = 'e:e:k:s:g'test_str2 = 'g:e:e:k:s' # printing original stringsprint("The original string 1 is : " + str(test_str1))print("The original string 2 is : " + str(test_str2)) # initializing delim delim = ':' # == operator is used for comparisonres = sorted(test_str1.split(':')) == sorted(test_str2.split(':')) # printing result print("Are strings similar : " + str(res)) |
Output
The original string 1 is : e:e:k:s:g The original string 2 is : g:e:e:k:s Are strings similar : True
Method #2 : Using set() + split()
In this, instead of sort(), we convert strings to set(), to get ordering. This works only on unique character strings.
Python3
# Python3 code to demonstrate working of # Similar characters Strings comparison# Using set() + split() # initializing stringstest_str1 = 'e:k:s:g'test_str2 = 'g:e:k:s' # printing original stringsprint("The original string 1 is : " + str(test_str1))print("The original string 2 is : " + str(test_str2)) # initializing delim delim = ':' # == operator is used for comparison# removes duplicates and comparesres = set(test_str1.split(':')) == set(test_str2.split(':')) # printing result print("Are strings similar : " + str(res)) |
Output
The original string 1 is : e:k:s:g The original string 2 is : g:e:k:s Are strings similar : True
