Python – Row with Minimum Sum in Matrix

We can have an application for finding the lists with the minimum value and print it. This seems quite an easy task and may also be easy to code, but having shorthands to perform the same are always helpful as this kind of problem can come in web development.

Method #1 : Using reduce() + lambda
The above two function can help us achieving this particular task. The lambda function does the task of logic and iteration and reduce function does the task of returning the required result. Works in python 2 only.

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# Python code to demonstrate
# Minimum Sum row in Matrix
# using reduce() + lambda
  
# initializing matrix 
test_matrix = [[1, 3, 1], [4, 5, 3], [1, 2, 4]]
  
# printing the original matrix
print ("The original matrix is : " + str(test_matrix))
  
# using reduce() + lambda
# Minimum Sum row in Matrix
res = reduce(lambda i, j: i if sum(i) < sum(j) else j, test_matrix)
  
# printing result
print ("Minimum sum row is : " + str(res))

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Output :

The original matrix is : [[1, 3, 1], [4, 5, 3], [1, 2, 4]]
Minimum sum row is : [1, 3, 1]

 

Method #2 : Using min() + key
The min function can get the minimum of all the list and key is used to specify on what the min condition has to be applied that is summation in this case.

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# Python3 code to demonstrate
# Minimum Sum row in Matrix
# using min() + key
  
# initializing matrix 
test_matrix = [[1, 3, 1], [4, 5, 3], [1, 2, 4]]
  
# printing the original matrix
print ("The original matrix is : " + str(test_matrix))
  
# using min() + key
# Minimum Sum row in Matrix
res = min(test_matrix, key = sum)
  
# printing result
print ("Minimum sum row is : " + str(res))

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Output :

The original matrix is : [[1, 3, 1], [4, 5, 3], [1, 2, 4]]
Minimum sum row is : [1, 3, 1]



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