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# Python – Retain K match index values from other list

• Last Updated : 06 Mar, 2020

Sometimes, while working with Python lists, we can have a problem in which we need to retain only the strings with match a particular value from the corresponding list at same index. This can have application in many domains. Lets discuss certain ways in which this task can be performed.

Method #1 : Using list comprehension + `zip()`
The combination of above functionalities can be used to perform this task. In this, we extract the list after selective zipping of both the list matching K.

 `# Python3 code to demonstrate ``# Retain K match index values from other list``# using zip() + list comprehension`` ` `# Initializing lists``test_list1 ``=` `[``'Gfg'``, ``'is'``, ``'best'``, ``'for'``, ``'Geeks'``, ``'and'``, ``'CS'``]``test_list2 ``=` `[``4``, ``1``, ``4``, ``3``, ``4``, ``2``, ``4``]`` ` `# printing original lists``print``(``"The original list 1 is : "` `+` `str``(test_list1))``print``(``"The original list 2 is : "` `+` `str``(test_list2))`` ` `# Initializing K ``K ``=` `4`` ` `# Group elements from Dual List Matrix``# using zip() + list comprehension``res ``=` `[x ``for` `x, y ``in` `zip``(test_list1, test_list2) ``if` `y ``=``=` `K]``             ` `# printing result ``print` `(``"The filtered list : "` `+` `str``(res))`
Output :

The original list 1 is : [‘Gfg’, ‘is’, ‘best’, ‘for’, ‘Geeks’, ‘and’, ‘CS’]
The original list 2 is : [4, 1, 4, 3, 4, 2, 4]
The filtered list : [‘Gfg’, ‘best’, ‘Geeks’, ‘CS’]

Method #2 : Using `compress()` + list comprehension
This is yet another way in which this task can be performed. In this, we use compress() instead of zip() to solve the problem.

 `# Python3 code to demonstrate ``# Retain K match index values from other list``# using compress + list comprehension``from` `itertools ``import` `compress`` ` `# Initializing lists``test_list1 ``=` `[``'Gfg'``, ``'is'``, ``'best'``, ``'for'``, ``'Geeks'``, ``'and'``, ``'CS'``]``test_list2 ``=` `[``4``, ``1``, ``4``, ``3``, ``4``, ``2``, ``4``]`` ` `# printing original lists``print``(``"The original list 1 is : "` `+` `str``(test_list1))``print``(``"The original list 2 is : "` `+` `str``(test_list2))`` ` `# Initializing K ``K ``=` `4`` ` `# Group elements from Dual List Matrix``# using compress + list comprehension``res ``=` `list``(compress(test_list1, ``map``(``lambda` `ele: ele ``=``=` `K, test_list2)))``             ` `# printing result ``print` `(``"The filtered list : "` `+` `str``(res))`
Output :

The original list 1 is : [‘Gfg’, ‘is’, ‘best’, ‘for’, ‘Geeks’, ‘and’, ‘CS’]
The original list 2 is : [4, 1, 4, 3, 4, 2, 4]
The filtered list : [‘Gfg’, ‘best’, ‘Geeks’, ‘CS’]

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