Python | Replace sublist with other in list

Sometimes, while working with Python, we can have a problem in which we need to manipulate a list in such a way that we need to replace a sublist with other. This kind of problem is common in web development domain. Let’s discuss certain ways in which this task can be performed.

Method #1 : Using loop ( When sublist is given )
This method is employed in cases we know the sublist which is to replaced. We perform this task using loops and list slicing and divide the logic of finding the indices which needs to be manipulated first and then perform the replace.

# Python3 code to demonstrate working of 
# Replace sublist with other in list 
# Using loop (when sublist is given) 
  
# helper function to find elements  
def find_sub_idx(test_list, repl_list, start = 0): 
    length = len(repl_list) 
    for idx in range(start, len(test_list)): 
        if test_list[idx : idx + length] == repl_list: 
            return idx, idx + length 
  
# helper function to perform final task 
def replace_sub(test_list, repl_list, new_list): 
    length = len(new_list) 
    idx = 0
    for start, end in iter(lambda: find_sub_idx(test_list, repl_list, idx), None): 
        test_list[start : end] = new_list 
        idx = start + length 
  
# initializing list 
test_list = [4, 5, 6, 7, 10, 2] 
  
# printing original list 
print("The original list is : " + str(test_list)) 
  
# Replace list  
repl_list = [5, 6, 7] 
new_list = [11, 1] 
  
# Replace sublist with other in list 
# Using loop (when sublist is given) 
replace_sub(test_list, repl_list, new_list) 
  
# printing result  
print("List after replacing sublist : " + str(test_list)) 

Output :

The original list is : [4, 5, 6, 7, 10, 2]
List after replacing sublist : [4, 11, 1, 10, 2]

Method #2 : Using list slicing ( When sublist index is given )
This task becomes easier when we just need to replace a sublist basic on the start and ending index available and list slicing is sufficient in such cases to achieve solution to this problem.

# Python3 code to demonstrate working of 
# Replace sublist with other in list 
# Using list slicing ( When sublist index is given ) 
  
# initializing list 
test_list = [4, 5, 6, 7, 10, 2] 
  
# printing original list 
print("The original list is : " + str(test_list)) 
  
# Replace list  
repl_list_strt_idx = 1
repl_list_end_idx = 4
new_list = [11, 1] 
  
# Replace sublist with other in list 
# Using list slicing ( When sublist index is given ) 
test_list[repl_list_strt_idx : repl_list_end_idx] = new_list 
  
# printing result  
print("List after replacing sublist : " + str(test_list)) 

Output :

The original list is : [4, 5, 6, 7, 10, 2]
List after replacing sublist : [4, 11, 1, 10, 2]

My Personal Notes

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