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Python – Replace Non-Maximum Records
• Last Updated : 02 Jun, 2020

Sometimes, while working with Python records, we can have a problem in which we need to perform replace of all the records whose one element is not Maximum. This kind of problem can have application in many domains including day-day programming and web development domain. Let’s discuss certain ways in which this task can be performed.

Input :
test_list = [(1, 4), (9, 11)]
K = “Non-Max”
Output : [‘Non-Max’, (9, 11)]

Input :
test_list = [(9, 11), (9, 11), (9, 11)]
K = “Non-Max”
Output : [(9, 11), (9, 11), (9, 11)]

Method #1 : Using loop + `map() + filter()` + lambda
The combination of above functionalities can be used to perform this task. In this, we perform task of filtering using map() and filter function, after that allocation of values to non-maximum elements using brute force approach using loop.

 `# Python3 code to demonstrate working of ``# Replace Non-Maximum Records``# Using loop + map() + filter() + lambda`` ` `# initializing list``test_list ``=` `[(``1``, ``4``), (``9``, ``11``), (``4``, ``6``), (``6``, ``8``), (``9``, ``11``)]`` ` `# printing original list``print``(``"The original list is : "` `+` `str``(test_list))`` ` `# initializing K ``K ``=` `None` ` ` `# Replace Non-Maximum Records``# Using loop + map() + filter() + lambda``res ``=` `[]``temp ``=` `list``(``filter``(``lambda` `ele: ele ``=``=` `max``(test_list), test_list))``for` `ele ``in` `test_list:``    ``if` `ele ``not` `in` `temp:``        ``res.append(K)``    ``else` `:``        ``res.append(ele)`` ` `# printing result ``print``(``"The list after replacing Non-Maximum : "` `+` `str``(res)) `
Output :

```The original list is : [(1, 4), (9, 11), (4, 6), (6, 8), (9, 11)]
The list after replacing Non-Maximum : [None, (9, 11), None, None, (9, 11)]
```

Method #2 : Using list comprehension + `map() + filter() + lambda`
The combination of above functions can be used to perform this task. In this, we perform task using similar to above method, just difference being using list comprehension for allotting K.

 `# Python3 code to demonstrate working of ``# Replace Non-Maximum Records``# Using list comprehension + map() + filter() + lambda`` ` `# initializing list``test_list ``=` `[(``1``, ``4``), (``9``, ``11``), (``4``, ``6``), (``6``, ``8``), (``9``, ``11``)]`` ` `# printing original list``print``(``"The original list is : "` `+` `str``(test_list))`` ` `# initializing K ``K ``=` `None` ` ` `# Replace Non-Maximum Records``# Using list comprehension + map() + filter() + lambda``temp ``=` `list``(``filter``(``lambda` `ele: ele ``=``=` `max``(test_list), test_list))``res ``=` `[ele ``if` `ele ``in` `temp ``else` `K ``for` `ele ``in` `test_list]`` ` `# printing result ``print``(``"The list after replacing Non-Maximum : "` `+` `str``(res)) `
Output :
```The original list is : [(1, 4), (9, 11), (4, 6), (6, 8), (9, 11)]
The list after replacing Non-Maximum : [None, (9, 11), None, None, (9, 11)]
```

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