# Python – Replace Elements greater than K

• Last Updated : 02 Sep, 2020

Given element list, replace all elements greater than K with given replace character.

Input : test_list = [3, 4, 7, 5, 6, 7], K = 5, repl_chr = None
Output : [3, 4, None, 5, None, None]
Explanation : Characters are replaced by None, greater than 5.

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Input : test_list = [3, 4, 7, 5, 6, 7], K = 4, repl_chr = None
Output : [3, 4, None, None, None, None]
Explanation : Characters are replaced by None, greater than 4.

Method #1 : Using loop

In this, we check for elements greater than K, if found, they are replaced by replace character, otherwise old value is retained.

## Python3

 `# Python3 code to demonstrate working of ``# Replace Elements greater than K``# Using loop`` ` `# initializing list``test_list ``=` `[``3``, ``4``, ``7``, ``5``, ``6``, ``7``, ``3``, ``4``, ``6``, ``9``]`` ` `# printing original list``print``(``"The original list is : "` `+` `str``(test_list))`` ` `# initializing K ``K ``=` `5`` ` `# initializing repl_chr ``repl_chr ``=` `"NA"`` ` `res ``=` `[]``for` `ele ``in` `test_list:``     ` `    ``# replace if greater than K``    ``if` `ele > K :``        ``res.append(repl_chr)``    ``else` `:``        ``res.append(ele)`` ` `# printing result ``print``(``"The replaced list : "` `+` `str``(res))`
Output
```The original list is : [3, 4, 7, 5, 6, 7, 3, 4, 6, 9]
The replaced list : [3, 4, 'NA', 5, 'NA', 'NA', 3, 4, 'NA', 'NA']
```

Method #2 : Using list comprehension

This is one liner way to solve this problem. Similar method as above, just using one liner.

## Python3

 `# Python3 code to demonstrate working of ``# Replace Elements greater than K``# Using list comprehension`` ` `# initializing list``test_list ``=` `[``3``, ``4``, ``7``, ``5``, ``6``, ``7``, ``3``, ``4``, ``6``, ``9``]`` ` `# printing original list``print``(``"The original list is : "` `+` `str``(test_list))`` ` `# initializing K ``K ``=` `5`` ` `# initializing repl_chr ``repl_chr ``=` `"NA"`` ` `# one liner to solve problem``res ``=` `[repl_chr ``if` `ele > K ``else` `ele ``for` `ele ``in` `test_list]`` ` `# printing result ``print``(``"The replaced list : "` `+` `str``(res))`
Output
```The original list is : [3, 4, 7, 5, 6, 7, 3, 4, 6, 9]
The replaced list : [3, 4, 'NA', 5, 'NA', 'NA', 3, 4, 'NA', 'NA']
```

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