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# Python | Replace duplicates in tuple

• Last Updated : 05 Feb, 2023

Sometimes, while working with Python tuples, we can have a problem in which we need to remove tuples elements that occur more than one times and replace duplicas with some custom value. Let’s discuss certain ways in which this task can be performed.

Method #1 : Using set() + list comprehension
The combination of above functionalities can be used to perform this particular task. In this, we just initialize a set container and then replace the reoccurring elements with a value after checking its existence it’s existence in tuple.

## Python3

 `# Python3 code to demonstrate working of``# Replace duplicates in tuple``# using set() + list comprehension` `# initialize tuple``test_tup ``=` `(``1``, ``1``, ``4``, ``4``, ``4``, ``5``, ``5``, ``6``, ``7``, ``7``)` `# printing original tuple``print``(``"The original tuple is : "` `+` `str``(test_tup))` `# Replace duplicates in tuple``# using set() + list comprehension``temp ``=` `set``()``res ``=` `tuple``(ele ``if` `ele ``not` `in` `temp ``and` `not` `temp.add(ele)``                ``else` `'gfg'` `for` `ele ``in` `test_tup)` `# printing result``print``(``"Tuple after replacing values : "` `+` `str``(res))`

Output :

```The original tuple is : (1, 1, 4, 4, 4, 5, 5, 6, 7, 7)
Tuple after replacing values : (1, 'gfg', 4, 'gfg', 'gfg', 5, 'gfg', 6, 7, 'gfg')```

Method #2 : Using groupby() + loop
The combination of above functionalities can be solved using this problem. In this, we just group the consecutive elements and then replace each element except for 1st with default value. Works only in case of consecutive duplicates.

## Python3

 `# Python3 code to demonstrate working of``# Replace duplicates in tuple``# using groupby() + loop``from` `itertools ``import` `groupby` `# initialize tuple``test_tup ``=` `(``1``, ``1``, ``4``, ``4``, ``4``, ``5``, ``5``, ``6``, ``7``, ``7``)` `# printing original tuple``print``(``"The original tuple is : "` `+` `str``(test_tup))` `# Replace duplicates in tuple``# using groupby() + loop``res ``=` `tuple``()``for` `key, ele ``in` `groupby(test_tup):``    ``res ``=` `res ``+` `((key, ) ``+` `(``'gfg'``, ) ``*` `(``len``(``list``(ele))``-``1``))` `# printing result``print``(``"Tuple after replacing values : "` `+` `str``(res))`

Output :

```The original tuple is : (1, 1, 4, 4, 4, 5, 5, 6, 7, 7)
Tuple after replacing values : (1, 'gfg', 4, 'gfg', 'gfg', 5, 'gfg', 6, 7, 'gfg')```

Method#3:Using dict.fromkeys

## Python3

 `# Python3 code to demonstrate working of``# Replace duplicates in tuple``# using dict.fromkeys and string value 'gfg'` `# initialize tuple``test_tup ``=` `(``1``, ``1``, ``4``, ``4``, ``4``, ``5``, ``5``, ``6``, ``7``, ``7``)` `# printing original tuple``print``(``"The original tuple is : "` `+` `str``(test_tup))` `# Replace duplicates in tuple``# using dict.fromkeys and string value 'gfg'``temp ``=` `set``()``res ``=` `tuple``(``'gfg'` `if` `ele ``in` `temp ``or` `temp.add(ele)``                ``else` `ele ``for` `ele ``in` `test_tup)` `# printing result``print``(``"Tuple after replacing values : "` `+` `str``(res))``#this code is contributed by Vinay pinjala.`

Output

```The original tuple is : (1, 1, 4, 4, 4, 5, 5, 6, 7, 7)
Tuple after replacing values : (1, 'gfg', 4, 'gfg', 'gfg', 5, 'gfg', 6, 7, 'gfg')```

Time complexity: O(n)

Auxiliary Space: O(n)

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