# Python | Remove unidentical lists

Sometimes, while working with python list, we can have a binary matrix ( Nested list having 2 elements ). And we can have a problem in which we need to remove unidentical lists. A pair is unique irrespective of order, it doesn’t appear again in list. Let’s discuss certain way in which this task can be performed.

Method : Using `frozenset() + Counter()` + list comprehension
The combination of above functions can perform this task. The frozenset() is used for ignoring the ordering, Counter() is used to perform the task of checking the uniqueness and iteration is done using list comprehension.

 `# Python3 code to demonstrate working of ` `# Remove unidentical lists ` `# using frozenset() + Counter() + list comprehension ` `from` `collections ``import` `Counter ` ` `  `# initialize list ` `test_list ``=` `[[``5``, ``6``], [``9``, ``8``], [``8``, ``9``], [``1``, ``4``], [``6``, ``5``], [``10``, ``1``]] ` ` `  `# printing original list ` `print``(``"The original list is : "` `+` `str``(test_list)) ` ` `  `# Remove unidentical lists ` `# using frozenset() + Counter() + list comprehension ` `temp ``=` `Counter(``frozenset``(ele) ``for` `ele ``in` `test_list) ` `res ``=` `[ele ``for` `ele ``in` `test_list ``if` `temp[``frozenset``(ele)] >``=` `2``] ` ` `  `# printing result ` `print``(``"The list after removal of unidentical lists : "` `+` `str``(res)) `

Output :

```The original list is : [[5, 6], [9, 8], [8, 9], [1, 4], [6, 5], [10, 1]]
The list after removal of unidentical lists : [[5, 6], [9, 8], [8, 9], [6, 5]]
```

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