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# Python – Remove Tuples of Length K

• Last Updated : 01 Aug, 2020

Given list of tuples, remove all the tuples with length K.

Input : test_list = [(4, 5), (4, ), (8, 6, 7), (1, ), (3, 4, 6, 7)], K = 2
Output : [(4, ), (8, 6, 7), (1, ), (3, 4, 6, 7)]
Explanation : (4, 5) of len = 2 is removed.

Input : test_list = [(4, 5), (4, ), (8, 6, 7), (1, ), (3, 4, 6, 7)], K = 3
Output : [(4, 5), (4, ), (1, ), (3, 4, 6, 7)]
Explanation : 3 length tuple is removed.

Method #1 : Using list comprehension

This is one of the ways in which this task can be performed. In this, we iterate for all elements in loop and perform the required task of removal of K length elements using conditions.

## Python3

 `# Python3 code to demonstrate working of ``# Remove Tuples of Length K``# Using list comprehension`` ` `# initializing list``test_list ``=` `[(``4``, ``5``), (``4``, ), (``8``, ``6``, ``7``), (``1``, ), (``3``, ``4``, ``6``, ``7``)]`` ` `# printing original list``print``(``"The original list : "` `+` `str``(test_list))`` ` `# initializing K ``K ``=` `1`` ` `# 1 liner to perform task``# filter just lengths other than K ``# len() used to compute length``res ``=` `[ele ``for` `ele ``in` `test_list ``if` `len``(ele) !``=` `K]`` ` `# printing result ``print``(``"Filtered list : "` `+` `str``(res))`
Output
```The original list : [(4, 5), (4, ), (8, 6, 7), (1, ), (3, 4, 6, 7)]
Filtered list : [(4, 5), (8, 6, 7), (3, 4, 6, 7)]

```

Method #2 : Using filter() + lambda + len()

Yet another way to solve this problem. In this, we perform filtering using filter() and lambda function to extract just non K length elements using len().

## Python3

 `# Python3 code to demonstrate working of ``# Remove Tuples of Length K``# Using filter() + lambda + len() `` ` `# initializing list``test_list ``=` `[(``4``, ``5``), (``4``, ), (``8``, ``6``, ``7``), (``1``, ), (``3``, ``4``, ``6``, ``7``)]`` ` `# printing original list``print``(``"The original list : "` `+` `str``(test_list))`` ` `# initializing K ``K ``=` `1`` ` `# filter() filters non K length values and returns result``res ``=` `list``(``filter``(``lambda` `x : ``len``(x) !``=` `K, test_list))`` ` `# printing result ``print``(``"Filtered list : "` `+` `str``(res))`
Output
```The original list : [(4, 5), (4, ), (8, 6, 7), (1, ), (3, 4, 6, 7)]
Filtered list : [(4, 5), (8, 6, 7), (3, 4, 6, 7)]

```

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