Python – Remove Keys with K value

Given a dictionary, remove all keys with value equals K.

Input : test_dict = {‘Gfg’ : 8, ‘is’ : 7, ‘best’ : 8, ‘for’ : 6, ‘geeks’ : 11}, K = 8
Output : {‘is’ : 7, ‘for’ : 6, ‘geeks’ : 11}
Explanation : “Gfg” and “Best”, valued 8, are removed.

Input : test_dict = {‘Gfg’ : 8, ‘is’ : 8, ‘best’ : 8, ‘for’ : 8, ‘geeks’ : 8}, K = 8
Output : {}
Explanation : All keys, valued 8, are removed.

Method #1 : Using dictionary comprehension

This is one of the ways in which this task can be performed. In this, we check for only elements that are not equal to K and retain it, inside dictionary comprehension as one-liner.



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# Python3 code to demonstrate working of 
# Remove Keys with K value
# Using dictionary comprehension
  
# initializing dictionary
test_dict = {'Gfg' : 6, 'is' : 7, 'best' : 9, 'for' : 6, 'geeks' : 11} 
  
# printing original dictionary
print("The original dictionary is : " + str(test_dict))
  
# initializing K 
K = 6
  
# using dictionary comprehension 
# to compare not equal to K and retain 
res = {key: val for key, val in test_dict.items() if val != K}
          
# printing result 
print("The filtered dictionary : " + str(res)) 

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Output


The original dictionary is : {'Gfg': 6, 'is': 7, 'best': 9, 'for': 6, 'geeks': 11}
The filtered dictionary : {'is': 7, 'best': 9, 'geeks': 11}





Method #2 : Using dict() + filter() + lambda


The combination of above functions can be used to solve this problem. In this, we filter all the non-K elements and retain. Finally the result is converted to dictionary using dict().




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# Python3 code to demonstrate working of  


# Remove Keys with K value 


# Using dict() + filter() + lambda 


  


# initializing dictionary 


test_dict = {'Gfg' : 6, 'is' : 7, 'best' : 9, 'for' : 6, 'geeks' : 11}  


  


# printing original dictionary 


print("The original dictionary is : " + str(test_dict)) 


  


# initializing K  


K = 6


  


# employing lambda for computation  


# filter() to perform filter according to lambda 


res = dict(filter(lambda key: key[1] != K, test_dict.items())) 


          


# printing result  


print("The filtered dictionary : " + str(res))  



















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Output


The original dictionary is : {'Gfg': 6, 'is': 7, 'best': 9, 'for': 6, 'geeks': 11}
The filtered dictionary : {'is': 7, 'best': 9, 'geeks': 11}







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