Python – Remove Keys with K value
Given a dictionary, remove all keys with value equals K.
Input : test_dict = {‘Gfg’ : 8, ‘is’ : 7, ‘best’ : 8, ‘for’ : 6, ‘geeks’ : 11}, K = 8
Output : {‘is’ : 7, ‘for’ : 6, ‘geeks’ : 11}
Explanation : “Gfg” and “Best”, valued 8, are removed.Input : test_dict = {‘Gfg’ : 8, ‘is’ : 8, ‘best’ : 8, ‘for’ : 8, ‘geeks’ : 8}, K = 8
Output : {}
Explanation : All keys, valued 8, are removed.
Method #1 : Using dictionary comprehension
This is one of the ways in which this task can be performed. In this, we check for only elements that are not equal to K and retain it, inside dictionary comprehension as one-liner.
Python3
# Python3 code to demonstrate working of # Remove Keys with K value# Using dictionary comprehension # initializing dictionarytest_dict = {'Gfg' : 6, 'is' : 7, 'best' : 9, 'for' : 6, 'geeks' : 11} # printing original dictionaryprint("The original dictionary is : " + str(test_dict)) # initializing K K = 6 # using dictionary comprehension # to compare not equal to K and retain res = {key: val for key, val in test_dict.items() if val != K} # printing result print("The filtered dictionary : " + str(res)) |
The original dictionary is : {'Gfg': 6, 'is': 7, 'best': 9, 'for': 6, 'geeks': 11}
The filtered dictionary : {'is': 7, 'best': 9, 'geeks': 11}
Method #2 : Using dict() + filter() + lambda
The combination of above functions can be used to solve this problem. In this, we filter all the non-K elements and retain. Finally the result is converted to dictionary using dict().
Python3
# Python3 code to demonstrate working of # Remove Keys with K value# Using dict() + filter() + lambda # initializing dictionarytest_dict = {'Gfg' : 6, 'is' : 7, 'best' : 9, 'for' : 6, 'geeks' : 11} # printing original dictionaryprint("The original dictionary is : " + str(test_dict)) # initializing K K = 6 # employing lambda for computation # filter() to perform filter according to lambdares = dict(filter(lambda key: key[1] != K, test_dict.items())) # printing result print("The filtered dictionary : " + str(res)) |
The original dictionary is : {'Gfg': 6, 'is': 7, 'best': 9, 'for': 6, 'geeks': 11}
The filtered dictionary : {'is': 7, 'best': 9, 'geeks': 11}
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