Python – Remove given character from first element of Tuple

Given a Tuple list, remove K character from 1st element of Tuple being String.

Input : test_list = [(“GF$g!”, 5), (“!i$s”, 4), (“best!$”, 10)], K = ‘$’ 

Output : [(‘GFg!’, 5), (‘!is’, 4), (‘best!’, 10)] 

Explanation : First element’s strings K value removed. 

Input : test_list = [(“GF$g!”, 5), (“best!$”, 10)], K = ‘$’ 

Output : [(‘GFg!’, 5), (‘best!’, 10)] 

Explanation : First element’s strings K value removed.

Method #1 : Using replace() + list comprehension

In this, we use replace() to perform the task of removing of K character and list comprehension to reform tuple.

Python3

# Python3 code to demonstrate working of
# Remove K character from first element of Tuple
# Using replace() + list comprehension

# initializing list
test_list = [("GF ! g !", 5), ("! i ! s", 4), ("best !!", 10)]

# printing original list
print("The original list is : " + str(test_list))

# initializing K
K = "!"

# replace with empty string removes the desired char.
res = [(sub[0].replace(K, ''), sub[1]) for sub in test_list]

# printing result
print("The filtered tuples : " + str(res))

Output

The original list is : [('GF!g!', 5), ('!i!s', 4), ('best!!', 10)]
The filtered tuples : [('GFg', 5), ('is', 4), ('best', 10)]

Method #2 : Using translate() + list comprehension

In this, we perform task of removal using translate(), which needs conversion to ASCII using ord(), and replaced with an empty character.

Python3

# Python3 code to demonstrate working of
# Remove K character from first element of Tuple
# Using translate() + list comprehension

# initializing list
test_list = [("GF ! g !", 5), ("! i ! s", 4), ("best !!", 10)]

# printing original list
print("The original list is : " + str(test_list))

# initializing K
K = "!"

# translation after conversion to ascii number
res = [(sub[0].translate({ord(K): None}), sub[1]) for sub in test_list]

# printing result
print("The filtered tuples : " + str(res))

Output

The original list is : [('GF!g!', 5), ('!i!s', 4), ('best!!', 10)]
The filtered tuples : [('GFg', 5), ('is', 4), ('best', 10)]

Method #3: Using for loop

Python3

# Python3 code to demonstrate working of
# Remove K character from first element of Tuple

# initializing list
test_list = [("GF!g!", 5), ("!i!s", 4), ("best!!", 10)]

# printing original list
print("The original list is : " + str(test_list))

# initializing K
res1 = []
K = "!"
for i in test_list:
    res = ""
    for j in i[0]:
        if(j != K):
            res += j
    x = (res, i[1])
    res1.append(x)


# printing result
print("The filtered tuples : " + str(res1))

Output

The original list is : [('GF!g!', 5), ('!i!s', 4), ('best!!', 10)]
The filtered tuples : [('GFg', 5), ('is', 4), ('best', 10)]

Time Complexity: O(n)
Auxiliary Space: O(n)

Method #4 : Using split() and join() methods

Approach

1. Initiate a for loop to traverse list of tuples
2. Split each first element of tuple by K and join by empty string
3. Append the joined string and second element of tuple together as tuple to output list
4. Display output list

Python3

# Python3 code to demonstrate working of
# Remove K character from first element of Tuple

# initializing list
test_list = [('GF$g!', 5), ('!i$s', 4), ('best!$', 10)]

# printing original list
print("The original list is : " + str(test_list))

# initializing K
K = "$"

# replace with empty string removes the desired char.
res=[]
for i in test_list:
    v=[]
    x=i[0].split(K)
    x="".join(x)
    v.append((x,i[1]))
    res.append(v)


# printing result
print("The filtered tuples : " + str(res))

Output

The original list is : [('GF$g!', 5), ('!i$s', 4), ('best!$', 10)]
The filtered tuples : [[('GFg!', 5)], [('!is', 4)], [('best!', 10)]]

Time Complexity : O(M*N) M- length of tuples list N – length of each tuple

Auxiliary Space : O(M*N) M- length of tuples list N – length of each tuple