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Python – Remove elements at Indices in List

  • Last Updated : 01 Dec, 2021

Given List, remove all the elements present in indices list.

Input : test_list = [5, 6, 3, 7, 8, 1, 2, 10], idx_list = [2, 4, 5] 
Output : [5, 6, 7, 2, 10] 
Explanation : 3, 6, and 1 has been removed.
Input : test_list = [5, 6, 3, 7, 8, 1, 2, 10], idx_list = [2] 
Output : [5, 6, 7, 8, 1, 2, 10] 
Explanation : 3 has been removed. 
 

Method #1 : Using enumerate() + loop

In this, we iterate for all the elements, and if index is present in list, then that index element is omitted from result list.

Python3




# Python3 code to demonstrate working of
# Remove elements at Indices in List
# Using loop
 
# initializing list
test_list = [5, 6, 3, 7, 8, 1, 2, 10]
 
# printing original list
print("The original list is : " + str(test_list))
 
# initializing idx list
idx_list = [2, 4, 5, 7]
 
res = []
for idx, ele in enumerate(test_list):
     
    # checking if element not present in index list
    if idx not in idx_list:
        res.append(ele)
 
# printing results
print("Filtered List after removal : " + str(res))
Output
The original list is : [5, 6, 3, 7, 8, 1, 2, 10]
Filtered List after removal : [5, 6, 7, 2]

Method #2 : Using enumerate() + list comprehension

In this, we perform task of iteration using list comprehension in compact way, rest all method similar to above.

Python3




# Python3 code to demonstrate working of
# Remove elements at Indices in List
# Using enumerate() + list comprehension
 
# initializing list
test_list = [5, 6, 3, 7, 8, 1, 2, 10]
 
# printing original list
print("The original list is : " + str(test_list))
 
# initializing idx list
idx_list = [2, 4, 5, 7]
 
# one-liner to test for element in index list
res = [ele for idx, ele in enumerate(test_list) if idx not in idx_list]
 
# printing results
print("Filtered List after removal : " + str(res))
Output
The original list is : [5, 6, 3, 7, 8, 1, 2, 10]
Filtered List after removal : [5, 6, 7, 2]

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