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Python – Remove elements at Indices in List
  • Last Updated : 02 Sep, 2020

Given List, remove all the elements present in indices list.

Input : test_list = [5, 6, 3, 7, 8, 1, 2, 10], idx_list = [2, 4, 5]
Output : [5, 6, 7, 2, 10]
Explanation : 3, 6, and 1 has been removed.

Input : test_list = [5, 6, 3, 7, 8, 1, 2, 10], idx_list = [2]
Output : [5, 6, 7, 8, 1, 2, 10]
Explanation : 3 has been removed.

Method #1 : Using enumerate() + loop

In this, we iterate for all the elements, and if index is present in list, then that index element is omitted from result list.



Python3




# Python3 code to demonstrate working of 
# Remove elements at Indices in List
# Using loop
  
# initializing list
test_list = [5, 6, 3, 7, 8, 1, 2, 10]
  
# printing original list
print("The original list is : " + str(test_list))
  
# initializing idx list 
idx_list = [2, 4, 5, 7]
  
res = []
for idx, ele in enumerate(test_list): 
      
    # checking if element not present in index list
    if idx not in idx_list:
        res.append(ele)
  
# printing results
print("Filtered List after removal : " + str(res))
Output
The original list is : [5, 6, 3, 7, 8, 1, 2, 10]
Filtered List after removal : [5, 6, 7, 2]

Method #2 : Using enumerate() + list comprehension

In this, we perform task of iteration using list comprehesion in compact way, rest all method similar to above.

Python3




# Python3 code to demonstrate working of 
# Remove elements at Indices in List
# Using enumerate() + list comprehension
  
# initializing list
test_list = [5, 6, 3, 7, 8, 1, 2, 10]
  
# printing original list
print("The original list is : " + str(test_list))
  
# initializing idx list 
idx_list = [2, 4, 5, 7]
  
# one-liner to test for element in index list
res = [ele for idx, ele in enumerate(test_list) if idx not in idx_list]
  
# printing results
print("Filtered List after removal : " + str(res))
Output
The original list is : [5, 6, 3, 7, 8, 1, 2, 10]
Filtered List after removal : [5, 6, 7, 2]

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