# Python | Remove element from given list containing specific digits

• Last Updated : 11 Oct, 2021

Given a list, the task is to remove all those elements from list which contains the specific digits.

Examples:

```Input: lst = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 14, 13, 15, 16]
no_delete = ['2', '3', '4', '0']
Output: [1, 5, 6, 7, 8, 9, 11, 15, 16]
Explanation:
Numbers 2, 3, 4, 10, 12, 13, 14 contains digits
from no_delete, therefore remove them.

Input: lst = [1, 2, 3, 4, 5, 6, 7, 8, 13, 15, 16]
no_delete = {'6', '5', '4', '3'}
Output: [1, 2, 7, 8, 9, 10, 11, 12]
Explanation:
Numbers 3, 4, 5, 6, 13, 14, 15, 16 contains digits
from no_delete, therefore remove them.
```

Below are some methods to do the task.

Method #1: Using Iteration

 `# Python code to remove all those elements ``# from list which contains certain digits`` ` `# Input List Initialisation``Input` `=` `[``1``, ``2``, ``3``, ``4``, ``5``, ``6``, ``7``, ``8``, ``9``, ``10``, ``11``, ``12``, ``14``, ``13``, ``15``, ``16``]`` ` `# Numbers to delete``no_delete ``=` `[``1``, ``0``]`` ` `# Output List Initialisation``Output ``=` `[]`` ` `# Using iteration to remove all the elements ``for` `elem ``in` `Input``:``    ``flag ``=` `1``    ``temp ``=` `elem``    ``while` `elem > ``0``:``        ``rem ``=` `elem ``%` `10``        ``elem ``=` `elem``/``/``10``        ``if` `rem ``in` `no_delete:``            ``flag ``=` `0``    ``if` `flag ``=``=` `1``:``        ``Output.append(temp)`` ` `# Printing Output ``print``(``"Initial list is :"``, ``Input``)``print``(``"Delete list :"``, no_delete)``print``(``"List after removing elements is :"``, Output)`

Output:

```Initial list is : [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 14, 13, 15, 16]
Delete list : [1, 0]
List after removing elements is : [2, 3, 4, 5, 6, 7, 8, 9]
```

Method #2: Using List comprehension and any() function

 `# Python code to remove all those elements from list ``# which contains certain digits`` ` `# Input List Initialisation``Input` `=` `[``1``, ``2``, ``3``, ``4``, ``5``, ``6``, ``7``, ``8``, ``9``, ``10``, ``11``, ``12``, ``14``, ``13``, ``15``, ``16``]`` ` `# Numbers to delete``no_delete ``=` `[``'2'``, ``'3'``, ``'4'``, ``'0'``]`` ` `# using list comprehension and any()``Output ``=` `[a ``for` `a ``in` `Input` `if` `not` `          ``any``(b ``in` `no_delete ``for` `b ``in` `str``(a))]`` ` `# Printing Output ``print``(``"Initial list is :"``, ``Input``)``print``(``"Delete list :"``, no_delete)``print``(``"List after removing elements is :"``, Output)`

Output:

```Initial list is : [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 14, 13, 15, 16]
Delete list : ['2', '3', '4', '0']
List after removing elements is : [1, 5, 6, 7, 8, 9, 11, 15, 16]
```

Method #3: Using List comprehension and set()

 `# Python code to remove all those elements from list ``# which contains certain digits`` ` `# Input List Initialisation``Input` `=` `[``1``, ``2``, ``3``, ``4``, ``5``, ``6``, ``7``, ``8``, ``9``, ``10``, ``11``, ``12``, ``14``, ``13``, ``15``, ``16``]`` ` `# Numbers to delete``no_delete ``=` `{``'6'``, ``'5'``, ``'4'``, ``'3'``}`` ` `# Using list comprehension and set``Output ``=` `[x ``for` `x ``in` `Input``         ``if` `not` `no_delete & ``set``(``str``(x))]`` ` `# Printing Output ``print``(``"Initial list is :"``, ``Input``)``print``(``"Delete list :"``, no_delete)``print``(``"List after removing elements is :"``, Output)`

Output:

```Initial list is : [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 14, 13, 15, 16]
Delete list : {'3', '4', '6', '5'}
List after removing elements is : [1, 2, 7, 8, 9, 10, 11, 12]
```

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