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Python | Remove duplicates based on Kth element tuple list
  • Last Updated : 03 Nov, 2019

Sometimes, while working with records, we may have a problem in which we need to remove duplicates based on Kth element of tuple in list. This problem has application in domains which uses records as input. Let’s discuss certain ways in which this problem can be solved.

Method #1 : Using loop
This is a brute force method to perform this particular task. In this, we check for the Kth index of tuple and add to a set to keep record. If that value is already in the memory set, we discard it from result as it’s duplicate.




# Python3 code to demonstrate working of
# Remove duplicates based on Kth element tuple list
# Using loop
  
# initialize list 
test_list = [(3, 1, 5), (1, 3, 6), (2, 1, 7),
                        (5, 2, 8), (6, 3, 0)]
  
# printing original list
print("The original list is : " + str(test_list))
  
# initialize K 
K = 1 
  
# Remove duplicates based on Kth element tuple list
# Using loop
temp = set()   
res = []
for ele in test_list:
    if ele[K] not in temp:
        res.append(ele)
        temp.add(ele[K])
  
# printing result
print("The list after removal of K based duplicates : " + str(res))
Output :

The original list is : [(3, 1, 5), (1, 3, 6), (2, 1, 7), (5, 2, 8), (6, 3, 0)]
The list after removal of K based duplicates : [(3, 1, 5), (1, 3, 6), (5, 2, 8)]

 



Method #2 : Using reduce() + lambda + keys()

In this method, we perform the task of filtering using reduce() + lambda, and decide to append or not using the extracted keys using keys(). If key has already occurred, its discarded otherwise added.




# Python3 code to demonstrate working of
# Remove duplicates based on Kth element tuple list
# Using reduce() + lambda + keys()
from functools import reduce
  
# initialize list 
test_list = [(3, 1), (1, 3), (3, 2), (5, 2), (5, 3)]
  
# printing original list
print("The original list is : " + str(test_list))
  
# initialize K 
K = 0
  
# Remove duplicates based on Kth element tuple list
# Using reduce() + lambda + keys()
res = reduce(lambda sub, ele : ele[K] in dict(sub).keys() 
                   and sub or sub + [ele], test_list, [])
  
# printing result
print("The list after removal of K based duplicates : " + str(res))
Output :

The original list is : [(3, 1), (1, 3), (3, 2), (5, 2), (5, 3)]
The list after removal of K based duplicates : [(3, 1), (1, 3), (5, 2)]

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