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Python – Remove Disjoint Tuple keys from Dictionary
  • Last Updated : 04 May, 2020

Sometimes, while working with Python dictionaries, we can have a problem in which we need to remove tuple keys from records on the basis of key presence matching any one of element present key from other lists. This kind of problem can have applications in data domains. Let’s discuss certain ways in which this task can be performed.

Input : test_dict = {(9, 3) : 4, (‘is’, 6) : 2, (‘for’, 9) : ‘geeks’}
Output : {}

Input : test_dict = {(‘is’, 9): 2, (‘for’, 8): 7}
Output : {(‘for’, 8): 7}

Method #1 : Using loop
This is one of the ways in which this task can be performed. In this we perform an iteration of dictionary key and check for the presence of any key in required and perform removal accordingly.

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# Python3 code to demonstrate working of 
# Remove Disjoint Tuple keys from Dictionary
# Using loop
  
# initializing dictionary
test_dict = {('Gfg', 3) : 4, ('is', 6) : 2, ('best', 10) : 3, ('for', 9) : 'geeks'}
  
# printing original dictionary
print("The original dictionary : " + str(test_dict))
  
# initializing List 
rem_list = [9, 'is']
  
# Remove Disjoint Tuple keys from Dictionary
# Using loop
res = dict()
for idx in test_dict:
    if idx[0] not in rem_list and idx[1] not in rem_list:
        res[idx] = test_dict[idx]
  
# printing result 
print("Dictionary after removal : " + str(res)) 

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Output :



The original dictionary : {(‘Gfg’, 3): 4, (‘best’, 10): 3, (‘for’, 9): ‘geeks’, (‘is’, 6): 2}
Dictionary after removal : {(‘Gfg’, 3): 4, (‘best’, 10): 3}

 

Method #2 : Using set() + dictionary comprehension + isdisjoint()
The combination of above functions can also be used to solve this problem. In this, we perform the task of comparison using isdisjoint().

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# Python3 code to demonstrate working of 
# Remove Disjoint Tuple keys from Dictionary
# Using set() + dictionary comprehension + isdisjoint()
  
# initializing dictionary
test_dict = {('Gfg', 3) : 4, ('is', 6) : 2, ('best', 10) : 3, ('for', 9) : 'geeks'}
  
# printing original dictionary
print("The original dictionary : " + str(test_dict))
  
# initializing List 
rem_list = [9, 'is']
  
# Remove Disjoint Tuple keys from Dictionary
# Using set() + dictionary comprehension + isdisjoint()
res = {keys: val for keys, val in test_dict.items() if set(keys).isdisjoint(rem_list)}
  
# printing result 
print("Dictionary after removal : " + str(res)) 

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Output :

The original dictionary : {(‘Gfg’, 3): 4, (‘best’, 10): 3, (‘for’, 9): ‘geeks’, (‘is’, 6): 2}
Dictionary after removal : {(‘Gfg’, 3): 4, (‘best’, 10): 3}

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