Given list of dictionaries with string list values, remove all the numerics from all strings.
Input : test_dict = {‘Gfg’ : [“G4G is Best 4”, “4 ALL geeks”], ‘best’ : [“Gfg Heaven”, “for 7 CS”]}
Output : {‘Gfg’: [‘GG is Best ‘, ‘ ALL geeks’], ‘best’: [‘Gfg Heaven’, ‘for CS’]}
Explanation : All the numeric strings are removed.Input : test_dict = {‘Gfg’ : [“G4G is Best 4”, “4 ALL geeks”]}
Output : {‘Gfg’: [‘GG is Best ‘, ‘ ALL geeks’]}
Explanation : All the numeric strings are removed.
Method : Using regex + dictionary comprehension
This problem can be solved using combination of both functionalities. In this, we apply regex to replace each digit with empty string and compile the result using dictionary comprehension.
Python3
# Python3 code to demonstrate working of # Remove digits from Dictionary String Values List # Using loop + regex() + dictionary comprehension import re # initializing dictionary test_dict = {'Gfg' : ["G4G is Best 4", "4 ALL geeks"], 'is' : ["5 6 Good"], 'best' : ["Gfg Heaven", "for 7 CS"]} # printing original dictionary print("The original dictionary is : " + str(test_dict)) # using dictionary comprehension to go through all keys res = {key: [re.sub('\d', '', ele) for ele in val] for key, val in test_dict.items()} # printing result print("The filtered dictionary : " + str(res)) |
The original dictionary is : {'Gfg': ['G4G is Best 4', '4 ALL geeks'], 'is': ['5 6 Good'], 'best': ['Gfg Heaven', 'for 7 CS']}
The filtered dictionary : {'Gfg': ['GG is Best ', ' ALL geeks'], 'is': [' Good'], 'best': ['Gfg Heaven', 'for CS']}
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