# Python – Remove all duplicate occurring tuple records

Sometimes, while working with records, we can have a problem of removing those records which occur more than once. This kind of application can occur in web development domain. Let’s discuss certain ways in which this task can be performed.

Method #1 : Using list comprehension +` set() + count()`
Initial approach that can be applied is that we can iterate on each tuple and check it’s count in list using count(), if greater than one, we can remove them, converting then to set.

 `# Python3 code to demonstrate working of ` `# Remove all Duplicate occurring records ` `# Using list comprehension + set() + count() ` ` `  `# initialize list ` `test_list ``=` `[(``3``, ``4``), (``4``, ``5``), (``3``, ``4``), (``3``, ``6``), (``4``, ``5``), (``6``, ``7``)] ` ` `  `# printing original list  ` `print``(``"The original list : "` `+` `str``(test_list)) ` ` `  `# Remove all Duplicate occurring records ` `# Using list comprehension + set() + count() ` `res ``=` `list``(``set``([ele ``for` `ele ``in` `test_list ``if` `not` `test_list.count(ele) > ``1``])) ` ` `  `# printing result ` `print``(``"All the non Duplicate from list are : "` `+` `str``(res)) `

Output :

```The original list : [(3, 4), (4, 5), (3, 4), (3, 6), (4, 5), (6, 7)]
All the non Duplicate from list are : [(6, 7), (3, 6)]
```

Method #2 : Using `Counter() + items()` + list comprehension
The combination of above functions can also be used to perform this particular task. In this, we just get the count of each occurrence of element using Counter() as dictionary and then extract all those whose value is equal to 1.

 `# Python3 code to demonstrate working of ` `# Remove all Duplicate occurring records ` `# Using list comprehension + Counter() + items() ` `from` `collections ``import` `Counter ` ` `  `# initialize list ` `test_list ``=` `[(``3``, ``4``), (``4``, ``5``), (``3``, ``6``), (``3``, ``4``), (``4``, ``5``), (``6``, ``7``)] ` ` `  `# printing original list  ` `print``(``"The original list : "` `+` `str``(test_list)) ` ` `  `# Remove all Duplicate occurring records ` `# Using list comprehension + Counter() + items() ` `res ``=` `[ele ``for` `ele, count ``in` `Counter(test_list).items() ``if` `count ``=``=` `1``] ` ` `  `# printing result ` `print``(``"All the non Duplicate from list are : "` `+` `str``(res)) `

Output :

```The original list : [(3, 4), (4, 5), (3, 4), (3, 6), (4, 5), (6, 7)]
All the non Duplicate from list are : [(6, 7), (3, 6)]
```

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