Python | Remove all digits from a list of strings

Given a list of strings, write a Python program to remove all digits from the list of string.

Examples:

Input : ['alice1', 'bob2', 'cara3']
Output : ['alice', 'bob', 'cara']

Input : ['4geeks', '3for', '4geeks']
Output : ['geeks', 'for', 'geeks']

Method #1 : Python Regex

Python regex pattern can also be used to find if each string contains a digit or not and converting them to “”.

# Python program to Remove all  
# digits from a list of string 
import re 
  
def remove(list): 
    pattern = '[0-9]'
    list = [re.sub(pattern, '', i) for i in list] 
    return list
  
# Driver code  
  
list = ['4geeks', '3for', '4geeks'] 
print(remove(list)) 

Output:

['geeks', 'for', 'geeks']

Method #2 : Using str.maketrans() method
The maketrans() method returns a translation table that maps each character in the intabstring into the character at the same position in the outtab string. In this particular problem we translate each each digit to “” using for loop.

# Python program to Remove all  
# digits from a list of string 
from string import digits 
  
def remove(list): 
    remove_digits = str.maketrans('', '', digits) 
    list = [i.translate(remove_digits) for i in list] 
    return list
  
# Driver code  
  
list = ['4geeks', '3for', '4geeks'] 
print(remove(list)) 

Output:

['geeks', 'for', 'geeks']

Method #3 : Using str.isalpha() method
In ,this approach we use two for loops and check if the character of string is an alphabet or not. If yes, join it within the list, otherwise leave it.

# Python program to Remove all  
# digits from a list of string 
from string import digits 
  
def remove(list): 
    list = [''.join(x for x in i if x.isalpha()) for i in list] 
              
    return list
  
# Driver code  
  
list = ['4geeks', '3for', '4geeks'] 
print(remove(list)) 

Output:

['geeks', 'for', 'geeks']

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