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Python – Remove after substring in String
  • Last Updated : 02 Sep, 2020

Given a String, remove all characters after particular substring.

Input : test_str = ‘geeksforgeeks is best for geeks’, sub_str = “for”
Output : geeksforgeeks is best for
Explanation : everything removed after for.

Input : test_str = ‘geeksforgeeks is best for geeks’, sub_str = “is”
Output : geeksforgeeks is
Explanation : everything removed after is.

Method #1 : Using index() + len() + slicing

In this, we first get the index of substring to perform removal after, add to that its length using len() and then slice off elements after that string using slicing.



Python3




# Python3 code to demonstrate working of 
# Remove after substring in String
# Using index() + len() + slicing
  
# initializing strings
test_str = 'geeksforgeeks is best for geeks'
  
# printing original string
print("The original string is : " + str(test_str))
  
# initializing sub string 
sub_str = "best"
  
# slicing off after length computation
res = test_str[:test_str.index(sub_str) + len(sub_str)]
  
# printing result 
print("The string after removal : " + str(res)) 
Output
The original string is : geeksforgeeks is best for geeks
The string after removal : geeksforgeeks is best

Method #2 : Using regex() ( for stripping off after numeric occurrence)

This is solution to a slightly different problem in which the string removal is required after numeric occurrence. We employ match operation and it retains all before match is found.

Python3




# Python3 code to demonstrate working of 
# Remove after substring in String
# Using regex() ( for stripping off after numeric occurrence)
import re
  
# initializing strings
test_str = 'geeksforgeeks is best 4 geeks'
  
# printing original string
print("The original string is : " + str(test_str))
  
# slicing after the numeric occurrence
res = re.match(r"(.*\d+)", test_str).group()
  
# printing result 
print("The string after removal : " + str(res)) 
Output
The original string is : geeksforgeeks is best 4 geeks
The string after removal : geeksforgeeks is best 4

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