# Python | Relative sorted order in Matrix

Sometimes, while working with Python Matrix, we can have data arranged randomly and we can have a requirement in which we need to get the element position in sorted order of Matrix. Let’s discuss a certain way in which this task can be performed.

Method : Using list comprehension + `enumerate() + sort() + lambda`
The solution to problem can be achieved using the combination of above functions. In these, we need to first arrange element for index value tuple creation using` enumerate()` and list comprehension. Then, we employ sort function to perform custom sort using lambda function.

Code :

 `# Python3 code to demonstrate working of ` `# Relative sorted order in Matrix ` `# using list comprehension + enumerate() + sort() + lambda ` ` `  `# initialize list ` `test_list ``=` `[[``1``, ``3``, ``1``], [``4``, ``6``], [``7``, ``8``, ``10``]] ` ` `  `# printing original list ` `print``(``"The original list is : "` `+` `str``(test_list)) ` ` `  `# Relative sorted order in Matrix ` `# using list comprehension + enumerate() + sort() + lambda ` `res ``=` `[(i, j) ``for` `i, x ``in` `enumerate``(test_list) ``for` `       ``j, _ ``in` `enumerate``(x)] ` `res.sort(key ``=` `lambda` `f: test_list[f[``0``]][f[``1``]]) ` ` `  `# printing result ` `print``(``"Sorted order of Matrix elements : "` `+` `str``(res)) `

Output :

```The original list is : [[1, 3, 1], [4, 6], [7, 8, 10]]
Sorted order of Matrix elements : [(0, 0), (0, 2), (0, 1), (1, 0),
(1, 1), (2, 0), (2, 1), (2, 2)]
```

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