Python – Reform K digit elements
Given the Python list, reform element to have K digits in a single element.
Input : test_list = [223, 67, 332, 1, 239, 2, 931], K = 2
Output : [22, 36, 73, 32, 12, 39, 29, 31]
Explanation : Elements reformed to assign 2 digits to each element.Input : test_list = [223, 67, 3327], K = 3
Output : [223, 673, 327]
Explanation : Elements reformed to assign 3 digits to each element.
Method #1 : Using slicing + join() + loop
In this, we perform task of joining all elements to single string, then slice K digits, and reconvert to list.
Python3
# Python3 code to demonstrate working of# Reform K digit elements# Using slicing + join() + loop # initializing listtest_list = [223, 67, 332, 1, 239, 2, 931] # printing original listprint("The original list is : " + str(test_list)) # initializing KK = 2 # converting to stringtemp = ''.join([str(ele) for ele in test_list]) # getting K digit slicesres = []for idx in range(0, len(temp), K): res.append(int(temp[idx: idx + K])) # printing resultprint("Reforming K digits : " + str(res)) |
Output
The original list is : [223, 67, 332, 1, 239, 2, 931] Reforming K digits : [22, 36, 73, 32, 12, 39, 29, 31]
Method #2 : Using list comprehension + join()
In this, task of reforming the list is done using list comprehension.
Python3
# Python3 code to demonstrate working of# Reform K digit elements# Using list comprehension + join() # initializing listtest_list = [223, 67, 332, 1, 239, 2, 931] # printing original listprint("The original list is : " + str(test_list)) # initializing KK = 2 # converting to stringtemp = ''.join([str(ele) for ele in test_list]) # getting K digit slices# using 1 liner list comprehensionres = [int(temp[idx: idx + K]) for idx in range(0, len(temp), K)] # printing resultprint("Reforming K digits : " + str(res)) |
Output
The original list is : [223, 67, 332, 1, 239, 2, 931] Reforming K digits : [22, 36, 73, 32, 12, 39, 29, 31]
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