# Python | Records with Key’s value greater than K

• Last Updated : 23 Jan, 2020

The problem of getting the suitable dictionaries that has a atleast value of the corresponding key is quite common when one starts working with dictionary. Let’s discuss certain ways in which this task can be performed.

Method #1 : Using loop
This is the brute force method by which this task can be performed. For this, we just use naive check and compare and append the records which have a particular key’s value greater than K.

 `# Python3 code to demonstrate working of``# Records with Key's value greater than K``# Using loop`` ` `# Initialize list``test_list ``=` `[{``'gfg'` `: ``2``, ``'is'` `: ``4``, ``'best'` `: ``6``}, ``            ``{``'it'` `: ``5``, ``'is'` `: ``7``, ``'best'` `: ``8``},``            ``{``'CS'` `: ``10``, ``'is'` `: ``8``, ``'best'` `: ``10``}]`` ` `# Printing original list``print``(``"The original list is : "` `+` `str``(test_list))`` ` `# Initialize K ``K ``=` `6`` ` `# Using loop``# Records with Key's value greater than K``res ``=` `[]``for` `sub ``in` `test_list:``    ``if` `sub[``'is'``] >``=` `K:``        ``res.append(sub)`` ` `# printing result ``print``(``"The filtered dictionary records is : "` `+` `str``(res))`
Output :
```The original list is : [{'best': 6, 'gfg': 2, 'is': 4}, {'best': 8, 'it': 5, 'is': 7}, {'best': 10, 'CS': 10, 'is': 8}]
The filtered dictionary records is : [{'best': 8, 'it': 5, 'is': 7}, {'best': 10, 'CS': 10, 'is': 8}]
```

Method #2 : Using `list()` + dictionary comprehension
The combination of these methods can also be used to perform this task. This difference is that it’s a one liner and more efficient as list function uses iterator as internal implementation which are quicker than generic methods.

 `# Python3 code to demonstrate working of``# Find dictionary matching value in list``# Using list() + dictionary comprehension`` ` `# Initialize list``test_list ``=` `[{``'gfg'` `: ``2``, ``'is'` `: ``4``, ``'best'` `: ``6``}, ``            ``{``'it'` `: ``5``, ``'is'` `: ``7``, ``'best'` `: ``8``},``            ``{``'CS'` `: ``10``, ``'is'` `: ``8``, ``'best'` `: ``10``}]`` ` `# Printing original list``print``(``"The original list is : "` `+` `str``(test_list))`` ` `# Initialize K ``K ``=` `6`` ` `# Using list() + dictionary comprehension``# Find dictionary matching value in list``res ``=` `list``((sub ``for` `sub ``in` `test_list ``if` `sub[``'is'``] >``=` `K))`` ` `# printing result ``print``(``"The filtered dictionary records : "` `+` `str``(res))`
Output :
```The original list is : [{'best': 6, 'gfg': 2, 'is': 4}, {'best': 8, 'it': 5, 'is': 7}, {'best': 10, 'CS': 10, 'is': 8}]
The filtered dictionary records is : [{'best': 8, 'it': 5, 'is': 7}, {'best': 10, 'CS': 10, 'is': 8}]
```

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