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Python | Records with Key’s value greater than K

  • Last Updated : 23 Jan, 2020

The problem of getting the suitable dictionaries that has a atleast value of the corresponding key is quite common when one starts working with dictionary. Let’s discuss certain ways in which this task can be performed.

Method #1 : Using loop
This is the brute force method by which this task can be performed. For this, we just use naive check and compare and append the records which have a particular key’s value greater than K.




# Python3 code to demonstrate working of
# Records with Key's value greater than K
# Using loop
  
# Initialize list
test_list = [{'gfg' : 2, 'is' : 4, 'best' : 6}, 
            {'it' : 5, 'is' : 7, 'best' : 8},
            {'CS' : 10, 'is' : 8, 'best' : 10}]
  
# Printing original list
print("The original list is : " + str(test_list))
  
# Initialize K 
K = 6
  
# Using loop
# Records with Key's value greater than K
res = []
for sub in test_list:
    if sub['is'] >= K:
        res.append(sub)
  
# printing result 
print("The filtered dictionary records is : " + str(res))
Output :
The original list is : [{'best': 6, 'gfg': 2, 'is': 4}, {'best': 8, 'it': 5, 'is': 7}, {'best': 10, 'CS': 10, 'is': 8}]
The filtered dictionary records is : [{'best': 8, 'it': 5, 'is': 7}, {'best': 10, 'CS': 10, 'is': 8}]

 

Method #2 : Using list() + dictionary comprehension
The combination of these methods can also be used to perform this task. This difference is that it’s a one liner and more efficient as list function uses iterator as internal implementation which are quicker than generic methods.




# Python3 code to demonstrate working of
# Find dictionary matching value in list
# Using list() + dictionary comprehension
  
# Initialize list
test_list = [{'gfg' : 2, 'is' : 4, 'best' : 6}, 
            {'it' : 5, 'is' : 7, 'best' : 8},
            {'CS' : 10, 'is' : 8, 'best' : 10}]
  
# Printing original list
print("The original list is : " + str(test_list))
  
# Initialize K 
K = 6
  
# Using list() + dictionary comprehension
# Find dictionary matching value in list
res = list((sub for sub in test_list if sub['is'] >= K))
  
# printing result 
print("The filtered dictionary records : " + str(res))
Output :
The original list is : [{'best': 6, 'gfg': 2, 'is': 4}, {'best': 8, 'it': 5, 'is': 7}, {'best': 10, 'CS': 10, 'is': 8}]
The filtered dictionary records is : [{'best': 8, 'it': 5, 'is': 7}, {'best': 10, 'CS': 10, 'is': 8}]

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