The problem of getting the suitable dictionaries that has a atleast value of the corresponding key is quite common when one starts working with dictionary. Let’s discuss certain ways in which this task can be performed.
Method #1 : Using loop
This is the brute force method by which this task can be performed. For this, we just use naive check and compare and append the records which have a particular key’s value greater than K.
# Python3 code to demonstrate working of# Records with Key's value greater than K# Using loop # Initialize listtest_list = [{'gfg' : 2, 'is' : 4, 'best' : 6}, {'it' : 5, 'is' : 7, 'best' : 8}, {'CS' : 10, 'is' : 8, 'best' : 10}] # Printing original listprint("The original list is : " + str(test_list)) # Initialize K K = 6 # Using loop# Records with Key's value greater than Kres = []for sub in test_list: if sub['is'] >= K: res.append(sub) # printing result print("The filtered dictionary records is : " + str(res)) |
The original list is : [{'best': 6, 'gfg': 2, 'is': 4}, {'best': 8, 'it': 5, 'is': 7}, {'best': 10, 'CS': 10, 'is': 8}]
The filtered dictionary records is : [{'best': 8, 'it': 5, 'is': 7}, {'best': 10, 'CS': 10, 'is': 8}]
Method #2 : Using list() + dictionary comprehension
The combination of these methods can also be used to perform this task. This difference is that it’s a one liner and more efficient as list function uses iterator as internal implementation which are quicker than generic methods.
# Python3 code to demonstrate working of# Find dictionary matching value in list# Using list() + dictionary comprehension # Initialize listtest_list = [{'gfg' : 2, 'is' : 4, 'best' : 6}, {'it' : 5, 'is' : 7, 'best' : 8}, {'CS' : 10, 'is' : 8, 'best' : 10}] # Printing original listprint("The original list is : " + str(test_list)) # Initialize K K = 6 # Using list() + dictionary comprehension# Find dictionary matching value in listres = list((sub for sub in test_list if sub['is'] >= K)) # printing result print("The filtered dictionary records : " + str(res)) |
The original list is : [{'best': 6, 'gfg': 2, 'is': 4}, {'best': 8, 'it': 5, 'is': 7}, {'best': 10, 'CS': 10, 'is': 8}]
The filtered dictionary records is : [{'best': 8, 'it': 5, 'is': 7}, {'best': 10, 'CS': 10, 'is': 8}]
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