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# Python – Rearrange list by other list order

• Last Updated : 10 May, 2020

Sometimes, while working with Python lists, we can have problem in which we need to perform sorting of lists according to other list ordering. This can have applications in many domains including day-day programming and school programming. Lets discuss certain ways in which this task can be performed.

Method #1 : Using List comprehension
This task can be performed using list comprehension. In this, we iterate the sort order list and simply append if list is present in target list. The indices are similar as per the sort order list.

 `# Python3 code to demonstrate working of ``# Rearrange list by other list order``# Using list comprehension`` ` `# initializing lists``test_list1 ``=` `[``5``, ``6``, ``7``, ``4``, ``8``, ``9``, ``2``]``test_list2 ``=` `[``9``, ``6``, ``4``]`` ` `# printing original list``print``(``"The original list 1 is : "` `+` `str``(test_list1))`` ` `# printing original list``print``(``"The original list 2 is : "` `+` `str``(test_list2))`` ` `# Rearrange list by other list order``# Using list comprehension``res ``=` `[ele ``for` `ele ``in` `test_list1 ``if` `ele ``in` `test_list2]`` ` `# printing result ``print``(``"The list after sorting is : "` `+` `str``(res)) `
Output :
```The original list 1 is : [5, 6, 7, 4, 8, 9, 2]
The original list 2 is : [9, 6, 4]
The list after sorting is : [6, 4, 9]
```

Method #2 : Using sorted + `index()`
The combination of above functions can also be used to perform this task. In this we use sort function with index as key to sort according to other list.

 `# Python3 code to demonstrate working of ``# Rearrange list by other list order``# Using sorted + index()`` ` `# initializing lists``test_list1 ``=` `[``5``, ``6``, ``7``, ``4``, ``8``, ``9``, ``2``]``test_list2 ``=` `[``9``, ``6``, ``4``]`` ` `# printing original list``print``(``"The original list 1 is : "` `+` `str``(test_list1))`` ` `# printing original list``print``(``"The original list 2 is : "` `+` `str``(test_list2))`` ` `# Rearrange list by other list order``# Using sorted + index()``res ``=` `sorted``(test_list2, key ``=` `test_list1.index)`` ` `# printing result ``print``(``"The list after sorting is : "` `+` `str``(res)) `
Output :
```The original list 1 is : [5, 6, 7, 4, 8, 9, 2]
The original list 2 is : [9, 6, 4]
The list after sorting is : [6, 4, 9]
```

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