Given a Matrix with variable lengths rows, extract last column.
Input : test_list = [[3, 4, 5], [7], [8, 4, 6], [10, 3]]
Output : [5, 7, 6, 3]
Explanation : Last elements of rows filtered.Input : test_list = [[3, 4, 5], [7], [8, 4, 6]]
Output : [5, 7, 6]
Explanation : Last elements of rows filtered.
Method #1 : Using loop
This is brute way to solve this, we access last element using “-1”, iterate for each row.
Python3
# Python3 code to demonstrate working of # Rear column in Multisized Matrix # Using loop # initializing list test_list = [[3, 4, 5], [7], [8, 4, 6, 1], [10, 3]] # printing original list print("The original list is : " + str(test_list)) res = [] for sub in test_list: # getting rear element using "-1" res.append(sub[-1]) # printing results print("Filtered column : " + str(res)) |
The original list is : [[3, 4, 5], [7], [8, 4, 6, 1], [10, 3]] Filtered column : [5, 7, 1, 3]
Method #2 : Using list comprehension
This is another way to solve this, in this, we perform above task in similar way, just as a shorthand.
Python3
# Python3 code to demonstrate working of # Rear column in Multisized Matrix # Using list comprehension # initializing list test_list = [[3, 4, 5], [7], [8, 4, 6, 1], [10, 3]] # printing original list print("The original list is : " + str(test_list)) # one-liner to solve this problem res = [sub[-1] for sub in test_list] # printing results print("Filtered column : " + str(res)) |
The original list is : [[3, 4, 5], [7], [8, 4, 6, 1], [10, 3]] Filtered column : [5, 7, 1, 3]
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