# Python – Rear column in Multi-sized Matrix

• Last Updated : 02 Sep, 2020

Given a Matrix with variable lengths rows, extract last column.

Input : test_list = [[3, 4, 5], [7], [8, 4, 6], [10, 3]]
Output : [5, 7, 6, 3]
Explanation : Last elements of rows filtered.

Input : test_list = [[3, 4, 5], [7], [8, 4, 6]]
Output : [5, 7, 6]
Explanation : Last elements of rows filtered.

Method #1 : Using loop

This is brute way to solve this, we access last element using “-1”, iterate for each row.

## Python3

 `# Python3 code to demonstrate working of ``# Rear column in Multisized Matrix``# Using loop`` ` `# initializing list``test_list ``=` `[[``3``, ``4``, ``5``], [``7``], [``8``, ``4``, ``6``, ``1``], [``10``, ``3``]]`` ` `# printing original list``print``(``"The original list is : "` `+` `str``(test_list))`` ` `res ``=` `[]``for` `sub ``in` `test_list:``     ` `    ``# getting rear element using "-1"``    ``res.append(sub[``-``1``])`` ` `# printing results``print``(``"Filtered column : "` `+` `str``(res))`

Output

```The original list is : [[3, 4, 5], [7], [8, 4, 6, 1], [10, 3]]
Filtered column : [5, 7, 1, 3]
```

Method #2 : Using list comprehension

This is another way to solve this, in this, we perform above task in similar way, just as a shorthand.

## Python3

 `# Python3 code to demonstrate working of ``# Rear column in Multisized Matrix``# Using list comprehension`` ` `# initializing list``test_list ``=` `[[``3``, ``4``, ``5``], [``7``], [``8``, ``4``, ``6``, ``1``], [``10``, ``3``]]`` ` `# printing original list``print``(``"The original list is : "` `+` `str``(test_list))`` ` `# one-liner to solve this problem``res ``=` `[sub[``-``1``] ``for` `sub ``in` `test_list]`` ` `# printing results``print``(``"Filtered column : "` `+` `str``(res))`

Output

```The original list is : [[3, 4, 5], [7], [8, 4, 6, 1], [10, 3]]
Filtered column : [5, 7, 1, 3]
```

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