# Python – Random insertion of elements K times

Given 2 list, insert random elements from List 2 to List 1, K times at random position.

Input : test_list = [5, 7, 4, 2, 8, 1], add_list = [“Gfg”, “Best”, “CS”], K = 2
Output : [5, 7, 4, 2, 8, 1, ‘Best’, ‘Gfg’]
Explanation : Random elements from List 2 are added 2 times.

Input : test_list = [5, 7, 4, 2, 8, 1], add_list = [“Gfg”, “Best”, “CS”], K = 1
Output : [5, 7, 4, 2, 8, 1, ‘Gfg’]
Explanation : Random elements from List 2 are added 1 times.

Method : Using randint() + list slicing + loop + choice()

In this, choice() is used to get random elements from list 2 to insert into list 1 and, randint() is used to get index at which this needs to be inserted. Then list slicing is used to remake list according to newer order.

## Python3

 `# Python3 code to demonstrate working of  ` `# Random insertion of elements K times ` `# Using randint() + list slicing + loop + choice() ` `import` `random ` ` `  `# initializing list ` `test_list ``=` `[``5``, ``7``, ``4``, ``2``, ``8``, ``1``] ` ` `  `# printing original list ` `print``(``"The original list : "` `+` `str``(test_list)) ` ` `  `# initializing add list  ` `add_list ``=` `[``"Gfg"``, ``"Best"``, ``"CS"``] ` ` `  `# initializing K  ` `K ``=` `3` ` `  `for` `idx ``in` `range``(K): ` `     `  `    ``# choosing index to enter element ` `    ``index ``=` `random.randint(``0``, ``len``(test_list)) ` `     `  `    ``# reforming list and getting random element to add ` `    ``test_list ``=` `test_list[:index] ``+` `[random.choice(add_list)] ``+` `test_list[index:] ` ` `  `# printing result  ` `print``(``"The created List : "` `+` `str``(test_list)) `

Output

```The original list : [5, 7, 4, 2, 8, 1]
The created List : [5, 7, 4, 2, 'Best', 8, 1, 'Best', 'Gfg']

```
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