Python Program to test whether the length of rows are in increasing order

Last Updated : 24 Oct, 2020

Given a Matrix, the following program is used to test if length all rows of a matrix are in increasing order or not. If yes, it returns True, otherwise False.

Input : test_list = [[3], [1, 7], [10, 2, 4], [8, 6, 5, 1, 4]]
Output : True
Explanation : 1 < 2 < 3 < 5, increasing lengths of rows, hence True.
Input : test_list = [[3], [1, 7], [10], [8, 6, 5, 1, 4]]
Output : False
Explanation : 1 <2 >1 < 5, Non-increasing lengths of rows, hence False.

Method 1 : Using loop and len()

In this, we are using loop to check whether the length of next row is greater than the present row, if not, result is flagged off.

Python3

# initializing list
test_list = [[3], [1, 7], [10, 2, 4], [8, 6, 5, 1, 4]]
  
# printing original list
print("The original list is : " + str(test_list))
  
res = True 
for idx in range(len(test_list) - 1) :
      
    # flag off in case next length is not greater
    # than current
    if len(test_list[idx + 1]) <= len(test_list[idx]):
        res = False 
        break
  
# printing result 
print("Are rows of increasing lengths ? : " + str(res))

Output:

The original list is : [[3], [1, 7], [10, 2, 4], [8, 6, 5, 1, 4]]
Are rows of increasing lengths ? : True

Method 2 : Using all() and list comprehension

In this, we test for next length being greater than the current length using len() and all() is used to check for all the rows.

Python3

# initializing list
test_list = [[3], [1, 7], [10, 2, 4], [8, 6, 5, 1, 4]]
  
# printing original list
print("The original list is : " + str(test_list))
  
# checking for truth for all rows in matrix
res = all(len(test_list[idx + 1]) > len(test_list[idx]) for idx in range(len(test_list) - 1))
  
# printing result 
print("Are rows of increasing lengths ? : " + str(res))

Output:

The original list is : [[3], [1, 7], [10, 2, 4], [8, 6, 5, 1, 4]]
Are rows of increasing lengths ? : True

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