Python Program to test if the String only Numbers and Alphabets
Given a String, our task is to write a Python program to check if string contains both numbers and alphabets, not either nor punctuations.
Examples:
Input : test_str = 'Geeks4Geeks' Output : True Explanation : Contains both number and alphabets. Input : test_str = 'GeeksforGeeks' Output : False Explanation : Doesn't contain number.
Method #1 : Using isalpha() + isdigit() + any() + all() + isalnum()
In this, we check for all digits containing is alphabets and numbers combination using all(), isalpha() and isdigit(). The any() and isalnum() is used to filter out possibility of punctuations.
Python3
# Python3 code to demonstrate working of# Test if string contains both Numbers and Alphabets only# Using isalpha() + isdigit() + any() + all() + isalnum() # initializing stringtest_str = 'Geeks4Geeks' # printing original stringprint("The original string is : " + str(test_str)) # conditional combination for getting result.res = not ((all(idx.isdigit() for idx in test_str) or (all(idx.isalpha() for idx in test_str)) or (any(not idx.isalnum() for idx in test_str)))) # printing resultprint("Does string contain both numbers and alphabets only? : " + str(res)) |
Output:
The original string is : Geeks4Geeks Does string contain both numbers and alphabets only? : True
Method #2 : Using regex
Using regex is one of the ways in which this problem can be solved.
Python3
# Python3 code to demonstrate working of# Test if string contains both Numbers and Alphabets only# Using regeximport re # initializing stringtest_str = 'Geeks4Geeks' # printing original stringprint("The original string is : " + str(test_str)) # conditional combination for getting result.res = bool(re.match("^(?=.*[a-zA-Z])(?=.*[\d])[a-zA-Z\d]+$", "A530")) # printing resultprint("Does string contain both numbers and alphabets only? : " + str(res)) |
Output:
The original string is : Geeks4Geeks Does string contain both numbers and alphabets only? : True
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