Given a Dictionary, the task is to write a python program to swap positions of dictionary items. The code given below takes two indices and swap values at those indices.
Input : test_dict = {‘Gfg’ : 4, ‘is’ : 1, ‘best’ : 8, ‘for’ : 10, ‘geeks’ : 9}, i, j = 1, 3
Output : {‘Gfg’: 4, ‘for’: 10, ‘best’: 8, ‘is’: 1, ‘geeks’: 9}
Explanation : (for : 10) and (is : 1) swapped order.
Input : test_dict = {‘Gfg’ : 4, ‘is’ : 1, ‘best’ : 8, ‘for’ : 10, ‘geeks’ : 9}, i, j = 2, 3
Output : {‘Gfg’: 4, ‘is’: 1, ‘for’: 10, ‘best’: 8, ‘geeks’: 9}
Explanation : (for : 10) and (best : 8) swapped order.
Method : Using items() and dict()
This task is achieved in 3 steps:
- First dictionary is converted to equivalent key value pairs in form of tuples,
- Next swap operation is performed in a Pythonic way.
- At last, tuple list is converted back to dictionary, in its required format.
Example:
Python3
# initializing dictionary test_dict = { 'Gfg' : 4 , 'is' : 1 , 'best' : 8 , 'for' : 10 , 'geeks' : 9 } # printing original dictionary print ( "The original dictionary is : " + str (test_dict)) # initializing swap indices i, j = 1 , 3 # conversion to tuples tups = list (test_dict.items()) # swapping by indices tups[i], tups[j] = tups[j], tups[i] # converting back res = dict (tups) # printing result print ( "The swapped dictionary : " + str (res)) |
Output:
The original dictionary is : {‘Gfg’: 4, ‘is’: 1, ‘best’: 8, ‘for’: 10, ‘geeks’: 9}
The swapped dictionary : {‘Gfg’: 4, ‘for’: 10, ‘best’: 8, ‘is’: 1, ‘geeks’: 9}
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