# Python program to sort tuples by frequency of their absolute difference

• Last Updated : 24 Jan, 2021

Given list of dual tuples, the task here is to write a python program that can sort them by frequency of their elements’ absolute difference.

Input : [(1, 6), (11, 3), (9, 1), (6, 11), (2, 10), (5, 7)]

Attention geek! Strengthen your foundations with the Python Programming Foundation Course and learn the basics.

To begin with, your interview preparations Enhance your Data Structures concepts with the Python DS Course. And to begin with your Machine Learning Journey, join the Machine Learning - Basic Level Course

Output : [(5, 7), (1, 6), (6, 11), (11, 3), (9, 1), (2, 10)]

Explanation : 7 – 5 = 2 occurs only 1 time. 5 occurs twice [( 6 – 1), (11 – 6)] and 8 occurs 3 times as difference.

Input : [(1, 6), (6, 11), (5, 7)]

Output : [(5, 7), (1, 6), (6, 11)]

Explanation : 7 – 5 = 2 occurs only 1 time. 5 occurs twice [( 6 – 1), (11 – 6)].

Method : Using sorted(), abs(), count() and list comprehension

In this, we perform task of computing each absolute difference using abs() and list comprehension. Then, sorted() and count() are used to sort tuples based on computed results of absolute difference.

Example:

## Python3

 `# initializing list``test_list ``=` `[(``1``, ``6``), (``11``, ``3``), (``9``, ``1``), (``6``, ``11``), (``2``, ``10``), (``5``, ``7``)]`` ` `# printing original list``print``(``"The original list is : "` `+` `str``(test_list))`` ` `# getting differences pairs``diff_list ``=` `[``abs``(x ``-` `y) ``for` `x, y ``in` `test_list]`` ` `# sorting list by computed differences``res ``=` `sorted``(test_list, key ``=` `lambda` `sub: diff_list.count(``abs``(sub[``0``] ``-` `sub[``1``])))`` ` `# printing result``print``(``"Sorted Tuples : "` `+` `str``(res))`

Output:

The original list is : [(1, 6), (11, 3), (9, 1), (6, 11), (2, 10), (5, 7)]

Sorted Tuples : [(5, 7), (1, 6), (6, 11), (11, 3), (9, 1), (2, 10)]

My Personal Notes arrow_drop_up