Python Program to Sort the list according to the column using lambda

Given a list, the task is to sort the list according to the column using the lambda approach. Examples:

Input : array = [[1, 3, 3], [2, 1, 2], [3, 2, 1]] Output : Sorted array specific to column 0, [[1, 3, 3], [2, 1, 2], [3, 2, 1]] Sorted array specific to column 1, [[2, 1, 2], [3, 2, 1], [1, 3, 3]] Sorted array specific to column 2, [[3, 2, 1], [2, 1, 2], [1, 3, 3]] Input : array = [[‘java’, 1995], [‘c++’, 1983], [‘python’, 1989]] Output : Sorted array specific to column 0, [[‘c++’, 1983], [‘java’, 1995], [‘python’, 1989]] Sorted array specific to column 1, [[‘c++’, 1983], [‘python’, 1989], [‘java’, 1995]]

Approach:

• sorted() built-in function in Python gives a new sorted list from an iterable.
• key parameter to specify a function to be called on each list element prior to making comparisons.
• lambda is used as a function to iterate on each element.
• key = lambda x:x[i] here i is the column on which respect to sort the whole list.

Below is the implementation. 

Python3

# Python code to sorting list
# according to the column

# sortarray function is defined
def sortarray(array):

    for i in range(len(array[0])):

        # sorting array in ascending
        # order specific to column i,
        # here i is the column index
        sortedcolumn = sorted(array, key = lambda x:x[i])

        # After sorting array Column 1
        print("Sorted array specific to column {}, \
        {}".format(i, sortedcolumn))

# Driver code
if __name__ == '__main__':

    # array of size 3 X 2
    array = [['java', 1995], ['c++', 1983],
             ['python', 1989]]

    # passing array in sortarray function
    sortarray(array)

Output:

Sorted array specific to column 0, [[‘c++’, 1983], [‘java’, 1995], [‘python’, 1989]] Sorted array specific to column 1, [[‘c++’, 1983], [‘python’, 1989], [‘java’, 1995]]

Time complexity: O(n*logn), as sorting is done.
Auxiliary Space: O(n),where n is length of array.

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