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Python Program to remove a specific digit from every element of the list
  • Difficulty Level : Hard
  • Last Updated : 13 Jan, 2021

Given list of elements, the task here is to write a Python program that can remove presence of all a specific digit from every element and then return the resultant list. 

Examples:

Input : test_list = [333, 893, 1948, 34, 2346], K = 3 
Output : [”, 89, 1948, 4, 246] 
Explanation : All occurrences of 3 are removed.

Input : test_list = [345, 893, 1948, 34, 2346], K = 5 
Output : [34, 893, 1948, 34, 2346] 
Explanation : All occurrences of 5 are removed. 
 

Method 1 : Using loop, str() and join()



In this, we perform the task of reforming elements by converting them to string and checking for each digit and ignoring while joining to get new element. Lastly each element is converted to integer using int().

Example:

Python3




# initializing list
test_list = [345, 893, 1948, 34, 2346]
  
# printing original list
print("The original list is : " + str(test_list))
  
# initializing K
K = 3
  
res = []
for ele in test_list:
  
    # joining using join(),
    if list(set(str(ele)))[0] == str(K) and len(set(str(ele))) == 1:
        res.append('')
    else:
        res.append(int(''.join([el for el in str(ele) if int(el) != K])))
  
# printing result
print("Modified List : " + str(res))

Output:

The original list is : [345, 893, 1948, 34, 2346]

Modified List : [45, 89, 1948, 4, 246]

Method 2 : Using list comprehension, int(), str() and join()

Similar to above method, joining is done using join() and interconversion is performed using int() and str().

Example:

Python3




# initializing list
test_list = [345, 893, 1948, 34, 2346]
  
# printing original list
print("The original list is : " + str(test_list))
  
# initializing K
K = 3
  
# list comprehension performing task as one liner
res = ['' if list(set(str(ele)))[0] == str(K) and len(set(str(ele))) == 1 else int(
    ''.join([el for el in str(ele) if int(el) != K])) for ele in test_list]
  
# printing result
print("Modified List : " + str(res))

Output:

The original list is : [345, 893, 1948, 34, 2346]

Modified List : [45, 89, 1948, 4, 246]

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