Python Program to print hollow half diamond hash pattern
Give an integer N and the task is to print hollow half diamond pattern.
Examples:
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Input : 6 Output : # # # # # # # # # # # # # # # # # # # # Input : 7 Output : # # # # # # # # # # # # # # # # # # # # # # # #
Approach:
The idea is to break the pattern into two parts:
- Upper part: For the upper half start the for loop with iterator (i) from 1 to n and one more for loop with iterator (j) from 1 to i.
# # # # # # # # # # # # #
- Lower part: For lower half start the for loop with iterator (n-1) to 1 and loop inside this for will remain same as for the upper half.
# # # # # # # # # # #
- Now we have to check this condition that if (i==j) or (j==1) then we have to print “#”, otherwise we have to print ” “(space).
Below is the implementation:
# python program to print # hollow half diamond star # function to print hollow# half diamond stardef hollow_half_diamond(N): # this for loop is for # printing upper half for i in range( 1, N + 1): for j in range(1, i + 1): # this is the condition to # print "#" only on the # boundaries if i == j or j == 1: print("#", end =" ") # print " "(space) on the rest # of the area else: print(" ", end =" ") print() # this for loop is to print lower half for i in range(N - 1, 0, -1): for j in range(1, i + 1): if j == 1 or i == j: print("#", end =" ") else: print(" ", end =" ") print() # Driver Codeif __name__ == "__main__": N = 7 hollow_half_diamond( N ) |
Output:
# # # # # # # # # # # # # # # # # # # # # # # #
Time Complexity: O(N^2)
