Given a list, the task here is to write a Python program to extract elements which are multiple of all elements of custom list.
Input : test_list = [4, 24, 8, 10, 12, 23], div_list = [6, 4]
Output : [24, 12]
Explanation : 24 and 12 divides 6 and 4 both.Input : test_list = [4, 24, 8, 10, 12, 23], div_list = [6, 4, 7]
Output : []
Explanation : No elements divides 6, 4 and 7.
Method 1: Using list comprehension and all()
In this, we perform task of checking for all elements to be multiple using % operator and all(). List comprehension is used to iterate through all the elements.
Python3
# initializing List test_list = [4, 24, 8, 10, 12, 23] # printing original list print("The original list is : " + str(test_list)) # initializing divisor list div_list = [6, 4] # using all() to test for all elements res = [ele for ele in test_list if all(ele % j == 0 for j in div_list)] # printing result print("All elements multiple of divisor list : " + str(res)) |
Output:
The original list is : [4, 24, 8, 10, 12, 23]
All elements multiple of divisor list : [24, 12]
Method 2: Using filter(), lambda and all()
In this, we perform task of filtering using filter() and lambda, rest all the operations are performed like above method.
Python3
# initializing List test_list = [4, 24, 8, 10, 12, 23] # printing original list print("The original list is : " + str(test_list)) # initializing divisor list div_list = [6, 4] # using all() to test for all elements # using filter() and lambda to perform filtering res = list(filter(lambda ele: all(ele % j == 0 for j in div_list), test_list)) # printing result print("All elements multiple of divisor list : " + str(res)) |
Output:
The original list is : [4, 24, 8, 10, 12, 23]
All elements multiple of divisor list : [24, 12]
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