The program must accept an integer N as the input. The program must print the desired pattern as shown in the example input/ output.
Examples:
Input : 41325
Output :
****
*
***
**
*****
Explanation: for a given integer print the number of *’s that are equivalent to each digit in the integer. Here the first digit is 4 so print four *sin the first line. The second digit is 1 so print one *. So on and the last i.e., the fifth digit is 5 hence print five *s in the fifth line.Input : 60710
Output :
******

*******
*

Approach
Read the input
For each digit in the integer print the corresponding number of *s
If the digit is 0 then print no *s and skip to the next line
# function to print the pattern def pattern(n): # traverse through the elements # in n assuming it as a string for i in n: # print  for every line print ( "" , end = "") # print i number of * s in # each line print ( "*" * int (i)) # get the input as string n = "41325" pattern(n) 
**** * *** ** *****
Alternate solution that takes integer as input :
n = 41325 x = [] while n> 0 : x.append(n % 10 ) n / / = 10 for i in range ( len (x)  1 ,  1 ,  1 ): print ( '' + x[i] * '*' ) # code contributed by Baivab Dash 
**** * *** ** *****
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