# Python Program to print digit pattern

The program must accept an integer N as the input. The program must print the desired pattern as shown in the example input/ output.

Examples:

Input : 41325
Output :
|****
|*
|***
|**
|*****
Explanation: for a given integer print the number of *’s that are equivalent to each digit in the integer. Here the first digit is 4 so print four *sin the first line. The second digit is 1 so print one *. So on and the last i.e., the fifth digit is 5 hence print five *s in the fifth line.

Input : 60710
Output :
|******
|
|*******
|*
|

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach
For each digit in the integer print the corresponding number of *s
If the digit is 0 then print no *s and skip to the next line

 `# function to print the pattern ` `def` `pattern(n): ` ` `  `    ``# traverse through the elements ` `    ``# in n assuming it as a string ` `    ``for` `i ``in` `n: ` ` `  `        ``# print | for every line ` `        ``print``(``"|"``, end ``=` `"") ` ` `  `        ``# print i number of * s in  ` `        ``# each line ` `        ``print``(``"*"` `*` `int``(i)) ` ` `  `# get the input as string         ` `n ``=` `"41325"` `pattern(n) `

Output:

```|****
|*
|***
|**
|*****
```

Alternate solution that takes integer as input :

 `n ``=` `41325` `x ``=` `[] ` `while` `n>``0``: ` `    ``x.append(n``%``10``) ` `    ``n ``/``/``=` `10` `for` `i ``in` `range``(``len``(x)``-``1``,``-``1``,``-``1``): ` `    ``print``(``'|'``+``x[i]``*``'*'``) ` ` `  `# code contributed by Baivab Dash `

Output:

```|****
|*
|***
|**
|*****
```

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Improved By : dbaivab

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