# Python Program to print all distinct uncommon digits present in two given numbers

Given two positive integers **A **and **B**, the task is to print the distinct digits in descending order, which are not common in the two numbers.

**Examples:**

Input:A = 378212, B = 78124590Output:9 5 4 3 0Explanation:All distinct digits present in the two numbers are {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}. The digits {1, 2, 6, 7} are common in both numbers.

Input:A = 100, B = 273Output:7 3 2 1 0Explanation:All distinct digits present in the two numbers are {0, 1, 2, 3, 7}. The digits {0, 1, 2, 3, 7} are common in both numbers.

**Approach: **The problem can be solved using sets, and lists in python. Follow the steps below to solve the problem:

- Convert both integers into strings.
- Now, store the equivalent integer values of the characters of the strings
**A**and**B**in the lists**lis1**and**lis2**, using map() function. - Convert both the lists
**lis1**and**lis2**to set**lis1**and**lis2**using the set() method. - Now, find the uncommon digits of both sets
**lis1**and**lis2**using the function symmetric_difference() and store it in a set, say**lis**. - After completing the above steps, convert the set
**lis**into list**lis**using list() method. - Finally, Sort the list in descending order and print the list
**lis**as the answer.

Below is the implementation of the above approach:

## Python3

`# Python implementation` `# of the above approach` ` ` `# Function to print uncommon digits` `# of two numbers in descending order` `def` `disticntUncommonDigits(A, B):` ` ` ` ` `# Stores digits of A as string` ` ` `A ` `=` `str` `(A)` ` ` ` ` `# Stores digits of B as string` ` ` `B ` `=` `str` `(B)` ` ` ` ` `# Stores the characters` ` ` `# of A in a integer list` ` ` `lis1 ` `=` `list` `(` `map` `(` `int` `, A))` ` ` ` ` `# Stores the characters` ` ` `# of B in a integer list` ` ` `lis2 ` `=` `list` `(` `map` `(` `int` `, B))` ` ` ` ` `# Converts lis1 to set` ` ` `lis1 ` `=` `set` `(lis1)` ` ` ` ` `# Converts lis2 to set` ` ` `lis2 ` `=` `set` `(lis2)` ` ` ` ` `# Stores the uncommon digits present` ` ` `# in the sets lis1 and lis2` ` ` `lis ` `=` `lis1.symmetric_difference(lis2)` ` ` ` ` `# Converts lis to list` ` ` `lis ` `=` `list` `(lis)` ` ` ` ` `# Sort the list in descending order` ` ` `lis.sort(reverse ` `=` `True` `)` ` ` ` ` `# Print the list lis` ` ` `for` `i ` `in` `lis:` ` ` `print` `(i, end ` `=` `" "` `)` ` ` `# Driver Code` ` ` ` ` `# Input` `A ` `=` `378212` `B ` `=` `78124590` ` ` `disticntUncommonDigits(A, B)` |

**Output:**

9 5 4 3 0

**Time Complexity:** O(log_{10}(A) + log_{10}(B))**Auxiliary Space:** O(log_{10}(A) + log_{10}(B))