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# Python program to omit K length Rows

• Last Updated : 12 Nov, 2020

Given a Matrix, remove rows with length K.

Input : test_list = [[4, 7], [8, 10, 12, 8], [10, 11], [6, 8, 10]], K = 2
Output : [[8, 10, 12, 8], [6, 8, 10]]
Explanation : [4, 7] and [10, 11] omitted as length 2 rows.

Input : test_list = [[4, 7], [8, 10, 12, 8], [10, 11], [6, 8, 10]], K = 3
Output : [[4, 7], [8, 10, 12, 8], [10, 11]]
Explanation : [6, 8, 10] omitted as length 3 rows.

Method #1 :  Using loop + len()

In this, we check for the length of each row using len(), if found to be equal to K, that row is omitted from Matrix.

## Python3

 `# Python3 code to demonstrate working of ``# Omit K length Rows``# Using loop + len()`` ` `# initializing list``test_list ``=` `[[``4``, ``7``],``             ``[``8``, ``10``, ``12``, ``8``],``             ``[``10``, ``11``], ``             ``[``6``, ``8``, ``10``]]`` ` `# printing original list``print``(``"The original list is : "` `+` `str``(test_list))`` ` `# initializing K ``K ``=` `2`` ` `res ``=` `[]``for` `row ``in` `test_list:``     ` `    ``# checking rows not K length``    ``if` `len``(row) !``=` `K :``        ``res.append(row)`` ` `# printing result ``print``(``"Filtered Matrix : "` `+` `str``(res))`

Output:

The original list is : [[4, 7], [8, 10, 12, 8], [10, 11], [6, 8, 10]]
Filtered Matrix : [[8, 10, 12, 8], [6, 8, 10]]

Method #2 : Using filter() + lambda + len()

In this, we use filter() to extract rows with lengths other than K. The lambda function is used to render length computation logic.

## Python3

 `# Python3 code to demonstrate working of ``# Omit K length Rows``# Using filter() + lambda + len()`` ` `# initializing list``test_list ``=` `[[``4``, ``7``],``             ``[``8``, ``10``, ``12``, ``8``],``             ``[``10``, ``11``], ``             ``[``6``, ``8``, ``10``]]`` ` `# printing original list``print``(``"The original list is : "` `+` `str``(test_list))`` ` `# initializing K ``K ``=` `4`` ` `# getting elements with length other than K ``res ``=` `list``(``filter``(``lambda` `row : ``len``(row) !``=` `K, test_list))`` ` `# printing result ``print``(``"Filtered Matrix : "` `+` `str``(res))`

Output:

The original list is : [[4, 7], [8, 10, 12, 8], [10, 11], [6, 8, 10]]
Filtered Matrix : [[4, 7], [10, 11], [6, 8, 10]]

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