Python Program To Multiply Two Numbers Represented By Linked Lists
Given two numbers represented by linked lists, write a function that returns the multiplication of these two linked lists.
Examples:
Input: 9->4->6 8->4 Output: 79464 Input: 3->2->1 1->2 Output: 3852
Solution:
Traverse both lists and generate the required numbers to be multiplied and then return the multiplied values of the two numbers.
Algorithm to generate the number from linked list representation:
1) Initialize a variable to zero 2) Start traversing the linked list 3) Add the value of the first node to this variable 4) From the second node, multiply the variable by 10 and also take the modulus of this value by 10^9+7 and then add the value of the node to this variable. 5) Repeat step 4 until we reach the last node of the list.
Use the above algorithm with both linked lists to generate the numbers.
Below is the program for multiplying two numbers represented as linked lists:
Python3
# Python3 to multiply two numbers # represented as Linked Lists # Linked list node class class Node: # Function to initialize the node def __init__( self , data): self .data = data self . next = None # Linked List Class class LinkedList: # Function to initialize the # LinkedList class. def __init__( self ): # Initialize head as None self .head = None # Function to insert a node at the # beginning of the Linked List def push( self , new_data): # Create a new Node new_node = Node(new_data) # Make next of the new Node # as head new_node. next = self .head # Move the head to point to # new Node self .head = new_node # Function to print the Linked # List def printList( self ): ptr = self .head while (ptr ! = None ): print (ptr.data, end = '') if ptr. next ! = None : print ( '->' , end = '') ptr = ptr. next print () # Multiply contents of two Linked # Lists def multiplyTwoLists(first, second): num1 = 0 num2 = 0 first_ptr = first.head second_ptr = second.head while first_ptr ! = None or second_ptr ! = None : if first_ptr ! = None : num1 = (num1 * 10 ) + first_ptr.data first_ptr = first_ptr. next if second_ptr ! = None : num2 = (num2 * 10 ) + second_ptr.data second_ptr = second_ptr. next return num1 * num2 # Driver code if __name__ = = '__main__' : first = LinkedList() second = LinkedList() # Create first Linked List 9->4->6 first.push( 6 ) first.push( 4 ) first.push( 9 ) # Printing first Linked List print ( "First list is: " , end = '') first.printList() # Create second Linked List 8->4 second.push( 4 ) second.push( 8 ) # Printing second Linked List print ( "Second List is: " , end = '') second.printList() # Multiply two linked list and # print the result result = multiplyTwoLists(first, second) print ( "Result is: " , result) # This code is contributed by kirtishsurangalikar |
Output:
First List is: 9->4->6 Second List is: 8->4 Result is: 79464
Time Complexity: O(max(n1, n2)), where n1 and n2 represents the number of nodes present in the first and second linked list respectively.
Auxiliary Space: O(1), no extra space is required, so it is a constant.
Please refer complete article on Multiply two numbers represented by Linked Lists for more details!
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