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Python program to find the character position of Kth word from a list of strings

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  • Difficulty Level : Medium
  • Last Updated : 05 Sep, 2020

Given a list of strings. The task is to find the index of the character position for the word, which lies at the Kth index in the list of strings.

Examples:

Input : test_list = [“geekforgeeks”, “is”, “best”, “for”, “geeks”], K = 21 
Output : 0
Explanation : 21st index occurs in “geeks” and point to “g” which is 0th element of word.

Input : test_list = [“geekforgeeks”, “is”, “best”, “for”, “geeks”], K = 15 
Output : 1
Explanation : 15th index occurs in “best” and point to “e” which is 1st element of word.

Method #1 : Using enumerate() + list comprehension

In this, we use nested enumerate() to check indices for words, and strings in the list, list comprehension is used to encapsulate logic in 1 liner.

Python3




# Python3 code to demonstrate working of
# Word Index for K position in Strings List
# Using enumerate() + list comprehension
  
# initializing list
test_list = ["geekforgeeks", "is", "best", "for", "geeks"]
  
# printing original list
print("The original list is : " + str(test_list))
  
# initializing K
K = 20
  
# enumerate to get indices of all inner and outer list
res = [ele[0] for sub in enumerate(test_list) for ele in enumerate(sub[1])]
  
# getting index of word
res = res[K]
  
# printing result
print("Index of character at Kth position word : " + str(res))

Output

The original list is : [‘geekforgeeks’, ‘is’, ‘best’, ‘for’, ‘geeks’]
Index of character at Kth position word : 2

 Method #2 : Using next() + zip() + count()

In this, we pair up the number of words with its counts using zip(), and accumulate till we don’t reach Kth Index.

Python3




# Python3 code to demonstrate working of
# Word Index for K position in Strings List
# Using next() + zip() + count()
from itertools import count
  
# initializing list
test_list = ["geekforgeeks", "is", "best", "for", "geeks"]
  
# printing original list
print("The original list is : " + str(test_list))
  
# initializing K
K = 20
  
# count() for getting count
# pairing using zip()
cnt = count()
res = next(j for sub in test_list for j, idx in zip(
    range(len(sub)), cnt) if idx == K)
  
# printing result
print("Index of character at Kth position word : " + str(res))

Output

The original list is : [‘geekforgeeks’, ‘is’, ‘best’, ‘for’, ‘geeks’]
Index of character at Kth position word : 2


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