Python program to find sum of absolute difference between all pairs in a list

Given a list of distinct elements, write a Python program to find the sum of absolute differences of all pairs in the given list.

Examples:

Input : [9, 2, 14] 
Output : 24 
Explanation: (abs(9-2) + abs(9-14) + abs(2-14))

Input : [1, 2, 3, 4]
Output : 10 
Explanation: (abs(1-2) + abs(1-3) + abs(1-4)
             + abs(2-3) + abs(2-4) + abs(3-4))

The first approach is the brute force approach, which has been previously discussed. Here, we will discuss the pythonic approaches.

Approach #1 : Using enumerate()
Enumerate() method adds a counter to an iterable and returns it in a form of enumerate object. In this method, we have a list ‘diffs’ which contains the absolute difference. We use two loops having two variables each. One to iterate through the counter and one for the list element. In every iteration, we check if the elements are similar or not. If not, find absolute difference and append it to diffs. Finally, find the sum of list. Since each pair will be counted twice, we divide the final sum by 2 and return it.

filter_none

edit
close

play_arrow

link
brightness_4
code

# Python3 program to find sum of 
# absolute differences in all pairs 
  
def sumPairs(lst): 
      
    diffs = []
    for i, x in enumerate(lst):
        for j, y in enumerate(lst):
            if i != j: 
                diffs.append(abs(x-y))
              
    return int(sum(diffs)/2)
    
# Driver program 
lst = [1, 2, 3, 4
print(sumPairs(lst))

chevron_right


Output:

10

 
Approach #2 : Using itertools
Python itertools consist of permutation() method. This method takes a list as an input and return an object list of tuples that contain all permutation in a list form. Here, to find absolute difference we essentially need a permutation of two elements. Since each pair will be counted twice, we divide the final sum by 2.

filter_none

edit
close

play_arrow

link
brightness_4
code

# Python3 program to find sum of 
# absolutre differences in all pairs 
import itertools
  
def sumPairs(lst): 
      
    diffs = [abs(e[1] - e[0]) for e in itertools.permutations(lst, 2)]
    return int(sum(diffs)/2)
    
# Driver program 
lst = [9, 8, 1, 16, 15
print(sumPairs(lst))

chevron_right


Output:

74


My Personal Notes arrow_drop_up


If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

Please Improve this article if you find anything incorrect by clicking on the "Improve Article" button below.




Article Tags :

Be the First to upvote.


Please write to us at contribute@geeksforgeeks.org to report any issue with the above content.