Given two dates, Write a Python program to find the total number of days between them. **Examples:**

Input :dt1 = 13/12/2018, dt2 = 25/2/2019Output :74 daysInput :dt1 = 01/01/2004, dt2 = 01/01/2005Output :365 days

**Naive Approach: **One Naive Solution is to start from *dt1 *and keep counting days till *dt2 *is reached. This solution requires more than O(1) time.

A Better and Simple solution is to count the total number of days before dt1 from i.e., total days from 00/00/0000 to *dt1*, then count the total number of days before *dt2*. Finally, return the difference between the two counts.

## Python3

`# Python3 program two find number of` `# days between two given dates` `# A date has day 'd', month 'm' and year 'y'` `class` `Date:` ` ` `def` `__init__(` `self` `, d, m, y):` ` ` `self` `.d ` `=` `d` ` ` `self` `.m ` `=` `m` ` ` `self` `.y ` `=` `y` `# To store number of days in all months from` `# January to Dec.` `monthDays ` `=` `[` `31` `, ` `28` `, ` `31` `, ` `30` `, ` `31` `, ` `30` `,` ` ` `31` `, ` `31` `, ` `30` `, ` `31` `, ` `30` `, ` `31` `]` `# This function counts number of leap years` `# before the given date` `def` `countLeapYears(d):` ` ` `years ` `=` `d.y` ` ` `# Check if the current year needs to be considered` ` ` `# for the count of leap years or not` ` ` `if` `(d.m <` `=` `2` `):` ` ` `years ` `-` `=` `1` ` ` `# An year is a leap year if it is a multiple of 4,` ` ` `# multiple of 400 and not a multiple of 100.` ` ` `return` `int` `(years ` `/` `4` `) ` `-` `int` `(years ` `/` `100` `) ` `+` `int` `(years ` `/` `400` `)` `# This function returns number of days between two` `# given dates` `def` `getDifference(dt1, dt2):` ` ` `# COUNT TOTAL NUMBER OF DAYS BEFORE FIRST DATE 'dt1'` ` ` `# initialize count using years and day` ` ` `n1 ` `=` `dt1.y ` `*` `365` `+` `dt1.d` ` ` `# Add days for months in given date` ` ` `for` `i ` `in` `range` `(` `0` `, dt1.m ` `-` `1` `):` ` ` `n1 ` `+` `=` `monthDays[i]` ` ` `# Since every leap year is of 366 days,` ` ` `# Add a day for every leap year` ` ` `n1 ` `+` `=` `countLeapYears(dt1)` ` ` `# SIMILARLY, COUNT TOTAL NUMBER OF DAYS BEFORE 'dt2'` ` ` `n2 ` `=` `dt2.y ` `*` `365` `+` `dt2.d` ` ` `for` `i ` `in` `range` `(` `0` `, dt2.m ` `-` `1` `):` ` ` `n2 ` `+` `=` `monthDays[i]` ` ` `n2 ` `+` `=` `countLeapYears(dt2)` ` ` `# return difference between two counts` ` ` `return` `(n2 ` `-` `n1)` `# Driver program` `dt1 ` `=` `Date(` `13` `, ` `12` `, ` `2018` `)` `dt2 ` `=` `Date(` `25` `, ` `2` `, ` `2019` `)` `print` `(getDifference(dt1, dt2), ` `"days"` `)` |

**Output:**

74 days

**Using Python datetime module**:

Python comes with an inbuilt *datetime* module which helps us to solve various datetime related problems. In order to find the difference between two dates we simply input the two dates with date type and subtract them, which in turn provides us the number of days between the two dates.

## Python3

`# Python3 program to find number of days` `# between two given dates` `from` `datetime ` `import` `date` `def` `numOfDays(date1, date2):` ` ` `return` `(date2` `-` `date1).days` ` ` `# Driver program` `date1 ` `=` `date(` `2018` `, ` `12` `, ` `13` `)` `date2 ` `=` `date(` `2019` `, ` `2` `, ` `25` `)` `print` `(numOfDays(date1, date2), ` `"days"` `)` |

**Output:**

74 days

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